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2 years ago

8

If F(x) and G(x) are two functions such that F(G(x)) = x then F(x) and G(x) are ..?

2 answers:

lana [24]2 years ago

4 0

They are inverse functions though to be completely thorough your teacher should have also put g(f(x)) = x as well. Though I can see what your teacher is aiming for at least.

The idea is that whatever the output of g(x) is, it's plugged into f(x) and the initial input is the result. So g(x) takes a step forward and f(x) takes a step back undoing everything g(x) did. Which is exactly what an inverse operation does.

olga_2 [115]2 years ago

3 0

If f(g(x))=x then they are inverse functions by definition

A is the answer

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Answer:

18 questions

Step-by-step explanation:

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2 years ago

What is 1 and 5/9 times 9

kolezko [41]

1 $\frac{5}{9}$ * 9= 14

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3 years ago

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weeeeeb [17]

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Step-by-step explanation:

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3 years ago

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He values in the table represent a linear function. How does the value of y change in relation to a change in the value of x?

Ivahew [28]

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Step-by-step explanation:

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2 years ago

Find the value of k if the distance between (2,k) and (6,7) is 4√2 unit

andreyandreev [35.5K]

Answer:

k = 3

Step-by-step explanation:

We have the distance formula: $d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$ . We can plug in $4\sqrt{2}$ = d, x2 = 6, x1=2, y2 = 7, y1 = k.

Then, we can solve the question using some algebra to find that k = 3.

Edit: Here is a step by step:

$4\sqrt{2} = \sqrt{(6-2)^2 + (7-k)^2}\\$

$(4\sqrt{2})^2 = (6-2)^2 + (7-k)^2$

$32 = (4)^2 + (7-k)^2$

$32 = 16 + (7-k)^2$

$32 - 16 = (7-k)^2$

$16 = (7-k)^2$

$\sqrt{16} = (7-k)$

$4 = 7-k$

$k = 3$

4 0

3 years ago