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Step2247 [10]
3 years ago
7

True or Faulse: The oxidation process occuring in the liver rids the bloodstream of 32% of the alcohol present

Health
2 answers:
Flauer [41]3 years ago
6 0

Answer:

The given statement is False.  

Explanation:

The oxidation process occurring in the liver cleanses the bloodstream of 90% of the alcohol present. Most of the alcohol in the body is broken down and remove from the blood as acetate by this way. 5% is excreted as urine and another 5% eliminated from exhaling and as acetic acid.  

Further explanation:

• Most alcohol in the blood stream is broken down by the enzyme alcohol dehydrogenase (ADH) in the liver.

  • 90% of the alcohol in the body will be removed like this.
  • Alcohol dehydrogenase enzyme breaks down alcohol into     acetaldehyde and aldehyde dehydrogenase enzyme rapidly breaks down acetaldehyde into acetate.  
  • 5% is eliminated from exhaling and as acetic acid, another 5% is excreted as urine.  
  • Microsomal ethanol oxidizing system is an alternative pathway to breakdown high level of alcohol in the blood stream.  

Learn more:

1. Alcohol consumption effects in liver :

brainly.com/question/13648078 (answer by mandhlelaz)

2. Primary site of alcohol metabolism :

brainly.com/question/13064168  (answer by BarrettArcher)

3. Aldehyde dehydrogenase:  brainly.com/question/13062762 (answer by vicobussa)

Keywords :

Liver, alcohol, alcohol dehydrogenase, aldehyde dehydrogenase

aev [14]3 years ago
5 0
I believe the correct answer is false. The oxidation process occurring in the liver rids the bloodstream of not 32% of the alcohol present rather 90% of the alcohol. Five percent is excreted in the urine. Another five percent eliminated from exhaling and the rest is formed into acetic acid.
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