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kupik [55]
3 years ago
5

Find (a) the slope of the curve at the given point P, and (b) an equation of the tangent line at P: y = 9x^2 + 5 ; P (2,41)

Mathematics
1 answer:
Flauer [41]3 years ago
6 0

Answer:

(a) 36

(b) y = 36x-31

Step-by-step explanation:

(a) dy/dx = 18x

slope of tangent at (2, 41) = 18(2)

= 36

(b) using y-y1 = m(x-x1)

y-41 = 36(x-2)

y = 36x-31

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I need help with these two equations
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for these you need to rearrange the equations and do substitutions.

 #3 = if x+y=5 then you know x = 5-y

 now substitute that equation for x in the 2nd one so x + 2y = 8 becomes

5-y + 2y = 8 2y - y becomes 1y which becomes y then subtract 5 from each side to get y =3

now replace y with 3 in the first equation x = 5-3 so x = 2 

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 same type of work for #4

2x-y=6 ,S0 y = 2X+6

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that becomes 4x +4x+12 = -4

8x+8 = 1, x =1

y = 2(1)-6 = -4

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USPshnik [31]
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