Find (a) the slope of the curve at the given point P, and (b) an equation of the tangent line at P: y = 9x^2 + 5 ; P (2,41)
1 answer:
Answer:
(a) 36
(b) y = 36x-31
Step-by-step explanation:
(a) dy/dx = 18x
slope of tangent at (2, 41) = 18(2)
= 36
(b) using y-y1 = m(x-x1)
y-41 = 36(x-2)
y = 36x-31
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