Question

Find (a) the slope of the curve at the given point P, and (b) an equation of the tangent line at P: y = 9x^2 + 5 ; P (2,41)

Answer 1

Answer:

(a) 36

(b) y = 36x-31

Step-by-step explanation:

(a) dy/dx = 18x

slope of tangent at (2, 41) = 18(2)

= 36

(b) using y-y1 = m(x-x1)

y-41 = 36(x-2)

y = 36x-31