If one box is inside the other box, then 5, as 2 pears would be inside the inner box, and 3 pears would be in the outer box. 5 pears total would be in the outer box (including the ones from the inner box)
I drew the segment and used Pythagorean theorem to solve for its measure. The line formed is the hypotenuse of the imaginary right triangle.
Among the choices only -1.33 and -1.25 is a feasible choice. But I am leaning towards -1.25 as the y-value of point F based on my diagram. Please see attachment.