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sweet [91]
3 years ago
12

In chickens, the allele for feathered legs (F) is dominant over the allele for bare legs (f). In a population of chickens on a f

arm, 240 chickens have feathered legs (FF or Ff), and 80 chickens have bare legs (ff). How many chickens can be expected to be heterozygous for feathered legs (Ff)? Assume that the conditions of Hardy-Weinberg equilibrium apply to the population.
Biology
1 answer:
exis [7]3 years ago
7 0

Answer:

0.5

Explanation:

According to Hardy-Weinberg equilibrium p2+2pq+q2=1 (p+q=1)

p2 is frequency of the dominant homozygous genotype

2pq is the frequency of the heterozygous genotype

q2 is the frequency of the recessive homozygous genotype

In the example above 80 chickens have bare legs (ff)-recessive homozygous which means that the frequency of that genotype is 80/240+80=0.25 (q2), frequency of the recessive allele is\sqrt{0.25}=0.5. This means that the frequency of the dominant allele (p) is 1-0.5=0.5

So, the frequency of the heterozygous genotype (2pq) is 2*0.5*0.5=0.5

The frequency of the dominant homozygous genotype is p2=0.25

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Complete the table of the stages for aerobic cellular respiration.
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Cellular respiration begins in the cytoplasm, where glucose is broken down for energy production.  In the presence of an oxygen rich  environment, eukaryotes may carry out aerobic respiration.

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Further Explanation:

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This forms a gradient where there is a differential in the number of protons on either side of the membrane the protons flow or re-enter the matrix through the enzyme ATP synthase, which makes the energy storage molecules of ATP from the reduction of ADP. At the end of the electron transport, three molecules of oxygen accept electrons and protons to form molecules of water...

Learn more about cellular life at brainly.com/question/11259903

Learn more about cellular respiration at brainly.com/question/11203046

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