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3 years ago

a circle pool at a water treatment facility has a radius of 6 meters. about how long is the outer rim of the pool?

Mathematics

2 answers:

Softa [21]3 years ago

8 0

Circumference = 2(Pi)r

r = 6

(2)(3.14)(6) = 37.68 m

Anna35 [415]3 years ago

5 0

The formula for calculating the circumference of a circle is 2*pi*r. Because pi does not have an end, we'll use 3.14, since that is the approximate value of pi.
2*6*3.14 = <span>37.68
The outer rim of the pool is about 37.68 meters long</span>

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If you drive 23 miles south, make a turn and drive 39 miles east, how far are you, in a straight line, from

Rom4ik [11]

Answer:

45.27 miles

Step-by-step explanation:

Pythagorean theorem

23^2 + 39^2 = d ^ 2

d = 45.27 miles

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2 years ago

If m = 5 and n = -2, evaluate 3m - 4n and n2 - m and find the product of the two expressions.

ddd [48]

Hence the correct answer is C) -23

Further explanation:

We have to put the values of m and n into both expression first separately and then multiply the answers.

Given expressions are:

$Exp\ 1:3m-4n\\Exp\ 2: n^2-m$

The values are:

$m=5\\n=-2$

Putting the values in expression 1:

$3m-4n\\=3(5)-4(-2)\\=15+8\\=23$

Putting the values of m and n in second expression

$n^2-m\\=(-2)^2-5\\=4-5\\=-1$

Multiplying both expressions:

$(3m-4n)(n^2-m)=23* (-1)=-23$

Hence the correct answer is C) -23

Keywords: Polynomials, Putting values in expressions

Learn more about polynomials at:

#LearnwithBrainly

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3 years ago

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Diano4ka-milaya [45]

Answer:

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3 years ago

Match each expression in the left column with the correct product in the right column.

lesya692 [45]

Answer:

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Step-by-step explanation:

1) √4 . √-3 . √-3

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$\sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2$

$\sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 =$ -6

2) √-4 . √-3 . √-3

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$\sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1}$

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$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{3} = (\sqrt{3})^2 = 3$

Therefore, √4 . √3 . √3 = 2 . 3 = 6

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