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3 years ago

a circle pool at a water treatment facility has a radius of 6 meters. about how long is the outer rim of the pool?

Mathematics

2 answers:

Softa [21]3 years ago

8 0

Circumference = 2(Pi)r

r = 6

(2)(3.14)(6) = 37.68 m

Anna35 [415]3 years ago

5 0

The formula for calculating the circumference of a circle is 2*pi*r. Because pi does not have an end, we'll use 3.14, since that is the approximate value of pi.
2*6*3.14 = 37.68
The outer rim of the pool is about 37.68 meters long

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Help me with these please!!

Len [333]

y = 0 for the x-intercept, so
2х - 5*0 = 60
2x = 60
x = 60/2 = 30
(30, 0)

x = 0 for the y-intercept, so:
2*0 - 5x = 60
-5x = 60
5x = -60
x = -30/5 = -12
(0, -12)

Answer is a) (0, -12)(30, 0)

4 0

3 years ago

Read 2 more answers

A rectangle has a length of 12 yards less than 3 times its width. If the area of the rectangle is 135 square yards, find the len

Aleonysh [2.5K]

Answer:

The length is 15 yards

Step-by-step explanation:

Given

Represent the width with W and length with L: So

$Area = 135yd^2$

$L=3W - 12$

Required

Determine the length of the rectangle:

Area is calculated as thus:

$Area = L * W$

Substitute 3W - 12 for L and 135 for Area

$135= (3W - 12) * W$

$135= 3W^2 - 12W$

Reorder:

$3W^2 - 12W - 135= 0$

Divide through by 3

$W^2 - 4W - 45 = 0$

Expand:

$W^2 - 9W + 5W - 45 = 0$

$W(W - 9) + 5(W - 9) = 0$

$(W + 5)(W-9) = 0$

$W + 5 = 0$ or $W - 9 = 0$

$W = -5$ or $W = 9$

But width can't be negative

So:

$W = 9$

Recall that: $L=3W - 12$

$L = 3 * 9 - 12$

$L = 15$

Hence, the length 15 yards

4 0

3 years ago

A machine for baking hay produces cylindrical bales that are 6 feet in diameter and 5 1/3 feet in height. Which is closest to th

GaryK [48]

We know that
diameter=6 ft----------> r=6/2------> r=3 ft
h=5 1/3 ft------> (5*3+1)/3-----> 16/3 ft
[volume of a cylindrical bales]=pi*r²*h----> pi*3²*16/3---> 150.72 cm³

the answer is the option
B 151 cm³

5 0

2 years ago

Maggie was doing research for her Ph.D. in physics when a 12 mg sample of radioactive material decayed to 3 mg in 26 minutes. De

netineya [11]

The general way to work this out is to solve the general expression for
the remaining quantity versus half-life, using logarithms. But that's not
necessary with these numbers.

Look at the numbers:

-- 3 mg is 1/4 of 12 mg.

-- 1/4 is the product of (1/2) x (1/2).

-- So the 3 mg is what's left of 12 mg after 2 half-lives.
The 26 minutes must be two half-lives.

-- The half-life of that substance is 26/2 = 13 minutes.

Go Maggie !

3 0

3 years ago

a supermarket sells 2 kg and 4 kg of sugar a shipment of 1100 bags of sugar has a total mass of 2900 kg. How many 2 kg bags and

Vaselesa [24]

There are 750 (2 kg) bags and 350 (4 kg) bags in the shipment

Step-by-step explanation:

The given is:

A supermarket sells 2 kg and 4 kg of sugar a shipment of 1100 bags of sugar
The total mass of the sugar is 2900 kg

We need to find how many 2 kg bags and 4 kg bags are in the shipment

Assume that x represents the number of 2 kg bags and y represents the number of 4 kg bags

∵ x is the number of 2 kg bags

∵ y is the number of 4 kg bags

∵ The total number of bags are 1100

- Add x and y, then equate the sum by 1100

∴ x + y = 1100 ⇒ (1)

∵ The total mass of sugar is 2900 kg

- Multiply x by 2 and y by 4 to find the mass of the bags, then

add the two product and equate them by 2900

∴ 2x + 4y = 2900 ⇒ (2)

Now we have a system of equations to solve it

Multiply equation (1) by -2 to eliminate x

∴ -2x - 2y = -2200 ⇒ (3)

- Add equations (2) and (3)

∴ 2y = 700

- Divide both sides by 2

∴ y = 350

- Substitute the value of y in equation (1) to find x

∵ x + 350 = 1100

- Subtract 350 from both sides

∴ x = 750

There are 750 (2 kg) bags and 350 (4 kg) bags in the shipment

Learn more:

You can learn more about the system of equations in brainly.com/question/6075514

#LearnwithBrainly

4 0

3 years ago