The value of x in the secants intersection is 1 units
The value of NM in the tangent and secant intersection is 51 units
<h3>How to find length when secant and tangent intersect?</h3>
The first question, two secant intersect outside the circle.
Therefore,
(6x + 8x)8x = (9 + 7)7
14x(8x) = 16(7)
112x² = 112
x² = 112 / 112
x = √1
x = 1
The second question, tangent and secant intersect,
Therefore,
(x + 3)² = (x - 3)(16 + x - 3)
(x + 3)² = (x - 3)(x + 13)
(x + 3)(x + 3) = (x - 3)(x + 13)
x² + 3x + 3x + 9 = x² + 13x - 3x - 39
x² + 9x + 9 = x² + 10x - 39
x² - x² + 9x - 10x = -39 - 9
-x = - 48
x = 48
NM = 48 + 3 = 51 units
learn more on secant and tangent here: brainly.com/question/12477905
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Answer: The Fuschia Bot clicks _6_ times in 0.75 sec,
Step-by-step explanation:
Multiply the unit rate by time:
.75 sec × 8 clicks/sec
Seconds cancel. .75(8) = 6 clicks
Answer:
d. skewed right
Step-by-step explanation:
The shape of the given distribution is rightly skewed. For a symmetric distribution mean and median are equal and if mean is greater than median then the distribution is rightly skewed and if mean is less than median then the distribution is skewed left.
In the given distribution mean is greater than median and so the given distribution is skewed right.
Answer:
1-1) A=6×5=30m² | P=6×2+5×2=12+10=22m
1-2) A=5×20=100mi² | P=5×2+20×2=10+40=50mi
2-1) A=16×6=96m² | P=16×2+6×2=32+12=44m
2-2) A=20×9=180km² | P=20×2+9×2=40+18=58km
3-1) A=14×17=238yd² | P=14×2+17×2=28+34=62yd
3-2) A=20×18=360mi² | 20×2+18×2=40+36=76mi
Answer:
#3: 81
Step-by-step explanation:
I haven't done this type of math in a while so I'm unsure about #1 and #2, but #3 is 81.
3^4 = 3 × 3 × 3 × 3
3^4 = 9 × 3 × 3
3^4 = 27 × 3
3^4 = 81
