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sergejj [24]
4 years ago
5

Below are two different functions, f(x) and g(x). What can be determined about their y-intercepts?

Mathematics
1 answer:
Svetllana [295]4 years ago
3 0
<h2>Hello!</h2>

The answer is:

The correct option is:

A) The function g(x) has a higher y-intercept.

<h2>Why?</h2>

To solve the problem, we need to find the y-intercept of the g(x) function, and then, compare to the y-intercept of the f(x) function which is equal to -1 (we can see it on the picture).

Also, we need to remember the slope-interception form of the line:

y=mx+b

So,

Finding the y-intercept of the g(x) function, we have:

Calculating the slope of the function, using the first two points (4,9) and (6,13), we have:

m=\frac{y_2-y_1}{x_2-x_1}\\\\m=\frac{13-9}{6-4}=\frac{4}{2}=2

Now,

Calculating the value of "b", we have:

Using the first point (4,9), the slope of the function, and the slope-intercept form of the function, we have:

y=mx+b

y=2x+b

9=2*(4)+b

9=8+b

9-8=b

b=1

So, the equation of the line will be:

y=2x+1

We know that "b" represents the y-intercept, so, the function g(x) has its y-intercept at y equal to 1.

Comparing, we have that the function f(x) has a y-intercept located at y equal to "-1" and the g(x) function has a y-intercept located at y equal to "1".

Hence, the correct option is:

A) The function g(x) has a higher y-intercept.

Have a nice day!

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Suppose that the weight of navel oranges is normally distributed with a mean µµ = 8 ounces, and a standard deviation σσ = 1.5 ou
monitta

Answer:

Hello some parts of your question is missing below is the missing part

c. If you randomly select a navel orange, what is the probability that it weighs between6.2 and 7 ounces

Answer: A) 0.0099

              B) 0.6796

              C) 0.13956

Step-by-step explanation:

weight of Navel oranges evenly distributed

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A ) percentage of oranges weighing more than 11.5 ounces

P( x > 11.5 ) = P ( \frac{x - u}{ std} > \frac{11.5-8}{1.5} )

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                    = P ( Z < 0.4667 ) = 0.6796

                    = 67.96%

C ) probability of orange selected weighing between 6.2 and 7 ounces?

P ( 6.2 < X < 7 ) = P (\frac{6.2-8}{1.5} <  \frac{x - u}{ std} < \frac{7-8}{1.5} )

                          = P ( -1.2 < Z < -0.66 )

                          = Ф ( -0.66 ) - Ф(-1.2) = 0.13956

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