y varies inversely with x.
Example:
If we multiply x by 2 we need to divide y by 2 too.
So,
If y = 16 and x = 1/2, find y when x = 32
Lets see, from 1/2 to 32 e need to multiply 1/2 by 64, right? So let's divide 16 by 64.
16/64 = 8/32 = 4/16 = 2/8 = 1/4
So we can say that:
If y = 16 when x = 1/2, y = 1/4 when x = 32.
For y=x^2-6x-11
complete the square
so roots
set y=0
0=x^2-6x-11
group x terms
0=(x^2-6x)-11
take 1/2 of linear coefient (-6) and square it
-6/2=-3, (-3)^2=9
add positive and neative to inside of parenthasees
0=(x^2-6x+9-9)-11
complete square
0=((x-3)^2-9)-11
expand
0=(x-3)^2-9-11
0=(x-3)^2-20
add 20 to both sides
20=(x-3)^2
sqrt both sides
remember positive and negative roots
+/-2√5=x-3
add 3 to both sides
3+/-2√5=x
so
x=3+2√5 and 3-2√5
Answer:
4
Step-by-step explanation:
use the distace formula:
square root of (x2-x1)^2 + (y2-y1)^2
give brainliest please
9514 1404 393
Answer:
n = 6
Step-by-step explanation:
Add 2 and collect terms
3n = 18
Divide by 3
n = 6
The experimental probability would be 33 out of 60 or 55%