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3 years ago

Which solution is extraneous ?

Mathematics

2 answers:

raketka [301]3 years ago

8 0

I believe the answer is D. 10

Alika [10]3 years ago

3 0

The answer you are looking for is c)7

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Can anyone help me?

suter [353]

Answer:

0.8

Step-by-step explanation:

3(5x+2)+10=4

=15x+6+10=4

After this step you subtract 6 from each side and then subtract 10 from each side and then after that you divide 15x on each side which will give you 0.8.

8 0

3 years ago

John finds a toy train set John finds a toy train set on sale for 20% off at a toy store. The original price was $35. John

Helen [10]

Well here's your answer straight <u><em>he must pay 29.82$ </em></u>and here's my work,

20% of 35 is 7 and since its 20% off we must subtract 35-7=28
Next it said there's a 6.5 tax so that means we are adding on to 28$
6.5 of 28 is 1.82 so we add 28+1.82 which equals your answer 29.82

5 0

3 years ago

117.369 is 24 3/10% of what number?

Tanya [424]

Let's look at the equation:
0.243x=117.369
Divide each side by 0.243.
X=483
So, the number is 483.

4 0

3 years ago

Find the period of the function. y=3 sin x/8

Alexus [3.1K]

Answer:

The period of given function is $Period = 16\pi$

So, Option B is correct.

Step-by-step explanation:

In this question we need to find the period of the function y= 3 sin x/8

The formula used to find period of function is: $\frac{2\pi }{b}$

We need to know the value of b.

To find the value of b we compare the standard equation with the equation of function given.

Standard Equation: y = a sin(bx - c) +d

Given Equation: y= 3 sin(x/8)

Comparing we get:

a= 3

b= 1/8

c= 0

d=0

So, we get the value of b i.e 1/8. Putting it in the formula to find period of given function.

$Period = \frac{2\pi }{b}$

$Period = \frac{2\pi }{\frac{1}{8}}$

Solving,

$Period = 2\pi *8$

$Period = 16\pi$

So, the period of given function is $Period = 16\pi$

5 0

3 years ago

Has anybody gotten a 100% on their FLVS Math segment exam?

Flura [38]

Answer:

i have

Step-by-step explanation:

3 0

2 years ago