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Butoxors [25]
4 years ago
7

Which of the following trigonometric ratios is equivalent to sin 4pi / 3?

Mathematics
1 answer:
emmainna [20.7K]4 years ago
7 0

Answer:

(A)

Step-by-step explanation:

The given trigonometric ratio is :

sin\frac{4{\pi}}{3}

On solving this, we get

sin\frac{4{\pi}}{3}

=sin240^{{\circ}}

=sin(180+60)

=-sin60^{{\circ}}

=-\frac{\sqrt{3}}{2}

(A) The given trigonometric ratio is :

cos\frac{5{\pi}}{6}

=cos150^{{\circ}}

=cos(180-30)

=-cos30^{{\circ}}

=-\frac{\sqrt{3}}{2}

Which is equivalent to the given trigonometric ratio, thus (A) is correct.

(B) The given trigonometric ratio is :

cos\frac{5{\pi}}{3}

=cos300^{{\circ}}

=cos(360-60)

=-cos60^{{\circ}}

=-\frac{1}{2}

which is not equivalent to the given trigonometric ratio, thus(B) is incorrect.

(C) The given trigonometric ratio is :

sin\frac{{\pi}}{3}

=\frac{\sqrt{3}}{2}

which is not equivalent to the given trigonometric ratio, thus(C) is incorrect.

(D) The given trigonometric ratio is :

sin\frac{7{\pi}}{6}

=sin210^{{\circ}}

=sin(180+30)

=-sin30^{{\circ}}

=-\frac{1}{2}

which is not equivalent to the given trigonometric ratio, thus(D) is incorrect.

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Which ecpression is equivalent to sqrt 8x^7y^8?
mars1129 [50]

Domain:\ x\geq0\ \wedge\ y\in\mathbb{R}

\sqrt{8x^7y^8}=\sqrt8\cdot\sqrt{x^7}\cdot\sqrt{y^8}=\sqrt{4\cdot2}\cdot\sqrt{x^6\cdot x}\cdot\sqrt{y^{4\cdot2}}\\\\=\sqrt4\cdot\sqrt2\cdot\sqrt{x^6}\cdot\sqrt{x}\cdot\sqrt{(y^4)^2}=2\sqrt2\cdot\sqrt{x^{3\cdot2}}\cdot\sqrt{x}\cdot y^4\\\\=2y^4\sqrt2\cdot\sqrt{(x^3)^2}\cdot\sqrt{x}=2y^4\sqrt{2x}\cdot x^3\\\\=\boxed{2x^3y^4\sqrt{2x}}

Used:\\\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{a^2}=a\ for\ a\geq0

7 0
4 years ago
I need this now plis
Scrat [10]
40% is the answer. It's okay to ask for help but if you can't even spell then you need to start studying more often.
4 0
3 years ago
F(2) if f(x) = 2x - 5
wariber [46]

Answer:

plug in 2 , answer is -1

Step-by-step explanation:

4-5= -1

6 0
3 years ago
Consider the quadratic equation x2 = 4x - 5. How many solutions does the equation have?
JulijaS [17]

Answer:

  • no real solutions
  • 2 complex solutions

Step-by-step explanation:

The equation can be rearranged to vertex form:

  x^2 -4x = -5 . . . . . . . . . subtract 4x

  x^2 -4x +4 = -5 +4 . . . . add 4

  (x -2)^2 = -1 . . . . . . . . . show the left side as a square

  x -2 = ±√-1 = ±i . . . . . . take the square root; the right side is imaginary

  x = 2 ± i . . . . . . . . . . . . . add 2. These are the complex solutions.

_____

<em>Comment on the question</em>

Every 2nd degree polynomial equation has two solutions. They may be real, complex, or (real and) identical. That is, there may be 0, 1, or 2 real solutions. This equation has 0 real solutions, because they are both complex.

3 0
3 years ago
4-2m&gt;7-3m show step by step
harina [27]
The first step for solving this expression is to move the variable -3m to the left side and then change its sign.
4 - 2m + 3m > 7
Now move the constant to the right side and change its sign.
-2m + 3m > 7 - 4
Collect the terms on the left side.
m > 7 - 4
Lastly,, subtract the numbers on the right side to get your final answer.
m > 3
Let me know if you have any further questions.
:)
6 0
4 years ago
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