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JulijaS [17]
4 years ago
14

Hurry!!!!!!!!!!!! Mark Brainliest!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Arisa [49]4 years ago
6 0
<span>V=<span>13</span>π∗<span>r2</span>∗h</span>
<span>V=<span>13</span>π∗<span>32</span>∗9</span>
<span>V=<span>13</span>π∗9∗9</span>
<span>V=<span>13</span>π∗81</span>
<span>V=<span>13</span>∗81π</span>
<span>V=27π</span>
<span>V≈27∗3.14</span>
<span>V≈84.78</span>
<span>The volume is approximately 84.78 cubic feet</span>
o-na [289]4 years ago
4 0
It's 1017.88 hope this helps
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(05.02) In the figure below, angle y and angle x form vertical angles. Angle x forms a straight line with the 50° angle and the
Irina18 [472]

<u>☁️</u><u>My Answer☁️:</u>

y = 90°

<u>✧My Step-by-step explanation✧:</u>

The angle x forms a straight line with the both the 50° angle and the 40° angle:

x + 50° + 40° = 180°

x = 90°

Which means…

y = x = 90°

3 0
3 years ago
Read 2 more answers
A specific laptop loses half of its value every six months. If the original cost was $1, 100 and the value of the laptop is now
svetlana [45]

Answer:

2 years! :)

Step-by-step explanation:

3 0
3 years ago
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the length of a soccer pitch is 20 m less than twice its width. the area of the pitch is 6000m^2. find its dimensions.
Setler79 [48]
X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:

x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60

x=60
2x-20=2(60)-20=120-20=100

Solution: the length is 100 m, and the width is 60 m.

To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.


8 0
3 years ago
How do I find A and B?
Damm [24]
90 for the box and 45 for the next angle

6 0
4 years ago
Can you change 6% into decimal?
djyliett [7]
I'm going to assume you mean 6% of 1. 6% of 1 is 0.06.
8 0
3 years ago
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