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GenaCL600 [577]
3 years ago
11

Geometry math question

Mathematics
2 answers:
igomit [66]3 years ago
6 0

An isosceles triangle is one where two sides are equal to each other. The third side is of a different length.

At first glance, choice A looks like the answer because we have two sides that are the same length (the sides of length 1). However, this triangle is not possible because 1+1 = 2 which is less then 3. For a triangle to be possible, adding up two sides must be larger than the third side. I'm using the triangle inequality theorem here.

This works for choice D since 6+6 = 12 which is greater than 5. Also 5+6 = 11 which is greater than 6. So the answer is choice D

sammy [17]3 years ago
4 0

In an isosceles triangle, at least two sides must have the same length. Any triangle with 3 different side lengths must be eliminated. That leaves choices A and D.

Now we deal with A. 1, 1, 3.

Since 1 + 1 = 2, and that is less than 3, you cannot form a triangle with sides of lengths 1, 1, and 3, so A. is eliminated.

The answer must be D., and the lengths in D. do allow for a triangle.

Answer: D. {6, 6, 5}

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<img src="https://tex.z-dn.net/?f=5%5Cfrac%7B42%7D%7B170%7D%20%20-%203%5Cfrac%7B80%7D%7B170%7D%20" id="TexFormula1" title="5\fra
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5\dfrac{42}{170}-3\dfrac{80}{170}=(5-3)+\left(\dfrac{42}{170}-\dfrac{80}{170}\right)\\\\=2+\left(-\dfrac{38}{170}\right)=2-\dfrac{32}{170}=1\dfrac{170}{170}-\dfrac{38}{170}\\\\=1\dfrac{170-38}{170}=1\dfrac{132}{170}=1\dfrac{132:2}{170:2}=1\dfrac{66}{85}


5\dfrac{42}{170}-3\dfrac{80}{170}=4\dfrac{170+42}{170}-3\dfrac{80}{170}\\\\=(4-3)+\left(\dfrac{212}{170}-\dfrac{80}{170}\right)=1+\dfrac{212-80}{170}\\\\=1+\dfrac{132}{170}=1\dfrac{132:2}{170:2}=1\dfrac{66}{85}

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