So even postive integers are by defention in form 2k where k is a natural number so
let the sum of even integers to n=S
S=2(1+2+3+4+5+6+7+8+......+k-1+k
divide bith sides of equation 1 by 2
0.5S=1+2+3+4+5+...........+k-1+k
S=2(k+(k-1)+..............................+2+1)
divide both sides of equation 2 by 2
0.5S=k+k-1+..............................+2+1)
by adding both we will get
___________________________
S=(k+1)(k)
so the sum will be equal to
S=

so let us test the equation
for the first 3 even number there sums will be
2+4+6=12
by our equation 3^2+3=12
gave us the same answer so our equation is correct
Answer:
it depend
Step-by-step explanation:
hopefully i help
The answer is -3x^2+10xy+8y^2
5
where are you people getting these like lol
Answer:
12 ≮ 12
False
Step-by-step explanation:
19 − 7 < 12
12 ≮ 12 (<--- line through the less than sign)
False
(I'm not 100% sure)