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Bas_tet [7]
4 years ago
10

What place value is the 5 in the following number, 123.465? earn 100 points!!!

Mathematics
2 answers:
GenaCL600 [577]4 years ago
6 0

Answer:

The place value of 5 in "123.465" is the thousandths

Step-by-step explanation:

The reason for this is because the "5" is 3 points behind the decimal, making it in the thousanths place.

Papessa [141]4 years ago
5 0

Answer:

it will be in the thousands  place for sure

Step-by-step explanation:

hope that helps =) i forgot there were a decimal point

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your cell phone company started a rewards club. For every three text sent, you get 15 points. You need 1800 points for prize. Ho
dangina [55]
You would put these in a fraction then cross multiply so 15/1800 and 3/x then you get 5400 equals 15x then divide by 15 on both sides to get x equals 360
3 0
3 years ago
Look at pic and answer pls
PtichkaEL [24]

(a)  x^{-5}

(b)  3x^{-7}

(c)  $\frac{4}{3}x^4

Solution:

To write each of the given expression in the form ax^n:

(a)  \frac{x^3}{x^8}

Using exponential rule: \frac{a^x}{a^y}=a^{x-y}

$\frac{x^3}{x^8}=x^{3-8}

$\frac{x^3}{x^8}=x^{-5}

(b) \frac{6x}{2x^8}

Divide numerator and denominator by the common factor 2, we get

$\frac{6x}{2x^8}=\frac{3x}{x^8}

Using exponential rule: \frac{a^x}{a^y}=a^{x-y}

      $=3x^{1-8}

$\frac{6x}{2x^8} =3x^{-7}

(c)  \frac{28x^6}{21x^2}

Divide numerator and denominator by the common factor 7, we get

$\frac{28x^6}{21x^2}=\frac{4x^6}{3x^2}

Using exponential rule: \frac{a^x}{a^y}=a^{x-y}

        $=\frac{4}{3}x^{6-2}

$\frac{28x^6}{21x^2}=\frac{4}{3}x^4

8 0
3 years ago
What is the terms of expression of 6g-h
Finger [1]
(6g) and (-h) are the 2 terms in the expression
8 0
3 years ago
FIND THE MESURES OF THE ANGLES. FIND TWO. ANSWER CHOICES:
Roman55 [17]

Answer:

<em>d</em><em> </em><em>.</em><em> </em><em>49</em>

Step-by-step explanation:

<em>180-131</em><em> </em><em>(</em><em> </em><em>supplementary</em><em> </em><em>angle</em><em>)</em>

<em>=</em><em> </em><em>49</em><em>°</em>

5 0
2 years ago
Read 2 more answers
Students in Mrs. Marquez's class are watching a film on the uses of geometry
Oxana [17]

The given information on the diagram of the projector and the image can

be used to prove the congruency of the triangles.

∠ABD, ∠BDA, and side \overline {AD} on ΔABD are congruent to ∠CBD, ∠BDC, and

segment \overline {CD} on ΔCBD, therefore, ΔABD ≅ ΔCBD, by <u>AAS Theorem</u>

Reasons:

The figure of the projector that casts an image on the screen is attached.

The bisector of the line \overline {AC} = \overline {BD}

From the drawing, we have;

∠ABD ≅ ∠CBD by equal number arc mark.

The two column proof is therefore, presented as follows;

Statement {}                                            Reason

\overline {BD} is perpendicular bisector of   {}\overline {AC}   Given

\overline {AD} = \overline {CD}   {}                                             Definition of bisected line \overline {AC}  

∠BDC = 90°       {}                                      \overline {BD} is perpendicular \overline {AC}  

∠BDA = 90°                         {}                    \overline {BD} is perpendicular \overline {AC}  

∠ABD ≅ ∠CBD {}                                       Given on the diagram

ΔABD ≅ ΔCBD  {}                          by Angle-Angle-Side AAS Congruency rule

The Angle-Angle-Side, AAS, Congruency postulate states that two

triangles are congruent where two adjacent angles and a non included side

on one triangle are congruent to the corresponding two adjacent angles

and a non included side on the other triangle.

Learn more here:

brainly.com/question/15274307

8 0
3 years ago
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