Question

Find the 14th term of the geometric sequence 10,−20,40,...

Answer 1

Obviously each term is multiplied by -2
an=a1 times r^(n-1)
a1=first term
r=common ratio
r=-2
a1=10

an=10 times (-2)^(n-1)
n=14=14th term
a14=10 times (-2)^(14-1)
a14=10 times (-2)^13
a14=10 times -8192
a14=-81920

it is -81920

Answer 2

The sequence is multiplying by -2, so
x = 10 * (-2)^n
x = 10 * (-2)^14
x = 10 * 16 384
x = 163 840