Y+12=-50 y=-62
To solve
Subtract 12 from each side of the equation
y=-62
Y=-62
To find the value for a in this equation, we can follow the next steps:
First, multiply all of the equation by 5:
Finally, add 115 to both sides of the equation:
Therefore, the value for a is a = -10.
The largest possible last digit in the string of 2002 digits and number divisible by 19 or 31 is 9.
Given the first digit of a string of 2002 digits is 1 and the two digit number formed by consecutive digits within the string is divisible by 19 or 31.
We have to tell the last largest digit of such number.
Two digit numbers divisible by 19=19,38,57,76,95.
Two digit numbers divisible by 31=31,62,93,124
Number started with 1 =19
Last digit is 9
We have said that the number should be divisible by 19 or 31 not from both and started with 1.
Hence the largest possible last digit and number divisible by 19 or 31 in this string is 9.
Learn more about digits at brainly.com/question/26856218
#SPJ4
Answer:
Step-by-step explanation:
If you examine the diagram you can know
<h3><u>Extra information</u><u> </u><u>:</u><u>-</u></h3>
In Triangle
ABC with the right angle at C, let a,b, and c be the opposite, the adjacent, and the hypotenuse of ∠A. Then, we have
sin A=ac⇒m∠A=sin−1(ac)
sin B=bc⇒m∠B=sin−1(bc)
I know its not the answer but I hope it was helpful
