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Andreyy89
3 years ago
14

Traffic signs are regulated by the Manual on Uniform Traffic Control Devices​ (MUTCD). The perimeter of a rectangular traffic si

gn is 140 inches.​ Also, its length is 10 inches longer than its width. Find the dimensions of this sign. What is the length of the​ sign?
Mathematics
1 answer:
sasho [114]3 years ago
5 0

The length and width of rectangular traffic sign are 40 and 30 inches respectively

<h3><u>Solution:</u></h3>

Given that,

Perimeter of rectangular traffic sign = 140 inches

Let length and width be denoted as ‘L’ and ‘B’ respectively

Given that length is 10 inches longer than its width

L = 10 + B

<em><u>The perimeter of rectangle is given as:</u></em>

Perimeter = 2( L + B)

On substituting the values, we get

140 = 2(10 + B + B)

140 = 2(10 + 2B)

140 = 20 + 4B

B = 30

Therefore, the length is L = 10 + 30 = 40

Hence the dimensions length and width of the rectangle are 40 and 30 inches respectively.  

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5 0
3 years ago
Graph the equation: x = y^2 - 2
Lesechka [4]
Draw a cartesian plane, create a graph with the equation x = y^2 - 2
then substitute numbers into the equation so that it is true, to find points on the graph, e.g. substitute y with 1, you get 
x = 1^2 - 2
x = 1 - 2 = -1, so when y = 1, x = -1, this point is (-1, 1)

for the next substitute y with 2,
x = 2^2 - 2
x = 4 - 2 = 2, the point is (2, 2)
you might want to try negative values of y 
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5 0
3 years ago
Joe began to increase the speed of his car at 2:00 P.M. Since that time,the speed of Joes car has been steadily increasing by 1
Olegator [25]

Answer:

7 mins

Step-by-step explanation:

Current speed of Joes Car = 65.5 mph

We have to find the time interval for which the car exceeded the speed limit of 55 mph.

While, we are given that the speed of the car was constantly increasing, hence the speed over all increased from the limit of 55 mph = 65.50-55.00 = 10.50 mph

We are also given that Joes car was increasing speed at a constant rate of 1.50 mph for every passing minute. Hence

1.50 mph is increased in 1 minute

1 mph will be increase in \frac{1}{1.5} minutes

Hence

10.50 mph will be increased in \frac{1}{1.5} \times 10.50 minutes

= \frac{10.5}{1.5}

=7

Hence joes car was exceeding the limit of 55 mph for 7 minutes.

8 0
3 years ago
gabriel put 6000 in a 2 year CD paying 4% interest, compounded monthly. After 2 years , he withdrew all his money. what was the
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amount after 2 years   = 6000(1 + (0.04/12))^24  = 6498.86
7 0
3 years ago
Read 2 more answers
HELP me plz someone!
Kamila [148]

Answer:

4,095 ft³

Step-by-step explanation:

V=LWH

V = 3 x 15 x 14

V= 4,095

4 0
3 years ago
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