The complex solutions come in pairs and the only difference between them is the sign between the real and imaginary part, so one of the other two solutions is
. The third solution can be easily found using the rational root theorem, and it's equal to -1.
The vector AB is not related with the vector CD as k is not the same for each pair of components.
<h3>Are two vectors similar?</h3>
In this question we must prove if the vector AB is a multiple of the vector CD, that is:
![\vec B - \vec A = k \cdot [\vec D - \vec C]](https://tex.z-dn.net/?f=%5Cvec%20B%20-%20%5Cvec%20A%20%3D%20k%20%5Ccdot%20%5B%5Cvec%20D%20-%20%5Cvec%20C%5D)
(1, 4) - (2, 3) = k · [(- 2, 2) - (1, 3)]
(- 1, 1) = k · (- 3, - 1)
Hence, the vector AB is not related with the vector CD as k is not the same for each pair of components.
To learn more on vectors: brainly.com/question/13322477
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<span>1.) Circumscribed angle 2.) Minor arc 3.) Central Angle 4.) Inscribed Angle 5.)Major Arc</span>
Answer:
R=9
Step-by-step explanation:
Change the sign of -2 to 2
Add 2 to 7
