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Andru [333]
3 years ago
12

this isn’t homework. but please help!! my wrist hurts a lot and i’m not totally sure why but this is what it looks like.

Mathematics
1 answer:
Tcecarenko [31]3 years ago
5 0

It dosen't look like anything is wrong with it. I would get it checked up if you are certain its something.

I hope this helps!

            - <em>DaMomsMom</em>

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5, 10.5, 22.05, 46.305, If it is a geometric sequence, choose the common ratio. If it is not a geometric sequence, choose "not g
kifflom [539]

Answer:

This is a geometric sequence since there is a common ratio between each term. In this case, multiplying the previous term in the sequence by  

2.1

gives the next term. In other words,  

a

n

=

a

1

⋅

r

n

−

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.

Geometric Sequence:  

r

=

2.1

This is the form of a geometric sequence.

a

n

=

a

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r

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−

1

Substitute in the values of  

a

1

=

5

and  

r

=

2.1

.

a

n

=

(

5

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⋅

(

2.1

)

n

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1

Remove parentheses around  

2.1

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a

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2.1

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Step-by-step explanation:


8 0
3 years ago
A sound wave enters a new medium where sound travels faster. How does this affect the frequency and wavelength of the sound?
worty [1.4K]
The frequency stays the same and the wavelength decreases.
6 0
3 years ago
Read 2 more answers
Which expression is equivalent to ^4sqrt6/^3sqrt2?
BigorU [14]

\dfrac{\sqrt[4]6}{\sqrt[3]2}=6^\frac{1}{4}:2^\frac{1}{3}=6^\frac{1\cdot3}{4\cdot3}:2^{\frac{1\cdot4}{3\cdot4}}=6^\frac{3}{12}:2^\frac{4}{12}=(6^3)^\frac{1}{12}:(2^4)^\frac{1}{12}\\\\=216^\frac{1}{12}:16^\frac{1}{12}=(216:16)^\frac{1}{12}=\sqrt[12]{\dfrac{216}{16}}=\sqrt[12]{\dfrac{27}{2}}\\\\\text{Answer:}\ 1)\ \sqrt[12]{\dfrac{27}{2}}

4 0
3 years ago
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Which table represents a nonlinear function?
Y_Kistochka [10]

Answer:C

Step-by-step explanation: When a table represents a nonlinear function, the rate of change is not constant. A wouldn't be the answer because the rate of change is always +10 (you would add 10 to get from -9 to 1; you would add 10 to get from 1 to 10) . It wouldn't be B because the rate of change is always -2, and the rate of change for D is always +3. For C, however, the rate of change is not constant all the way through (to get from 0 to 6, you would add 6, but to get from 6 to 16 you add 10).

5 0
3 years ago
The volume of a cone of radius r and height h is given by V=πr²h³. If the radius and the height both increase at a constant rate
Aloiza [94]

Answer:

The volume of cone is increasing at a rate 1808.64 cubic cm per second.

Step-by-step explanation:

We are given the following in the question:

\dfrac{dr}{dt} = 12\text{ cm per sec}\\\\\dfrac{dh}{dt} = 12\text{ cm per sec}

Volume of cone =

V = \dfrac{1}{3}\pi r^2 h

where r is the radius and h is the height of the cone.

Instant height = 9 cm

Instant radius = 6 cm

Rate of change of volume =

\dfrac{dV}{dt} = \dfrac{d}{dt}(\dfrac{1}{3}\pi r^2 h)\\\\\dfrac{dV}{dt} = \dfrac{\pi}{3}(2r\dfrac{dr}{dt}h + r^2\dfrac{dh}{dt})

Putting values, we get,

\dfrac{dV}{dt} = \dfrac{\pi}{3}(2(6)(12)(9) + (6)^2(12))\\\\\dfrac{dV}{dt} =1808.64\text{ cubic cm per second}

Thus, the volume of cone is increasing at a rate 1808.64 cubic cm per second.

5 0
3 years ago
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