What does a 100% increase mean

Factor 1 - 2.25x^8.

sleet_krkn [62]

<span>1 - 2.25x</span>⁸ =
1² - (1.5x⁴)² =
(1 + 1.5x⁴)(1 - 1.5x⁴)

5 0

3 years ago

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|-3 + 15| what is the sum (answer) ? I think it is 12 but my friend thinks it is 18. Who is right?

Aliun [14]

I do believe it is 12 as well considering the fact that it's negative three and not positive. If it was a positive three then maybe it would be 18.

4 0

3 years ago

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Calculate the annual interest for a $10,000 Treasury bond with a current yield of 3% that is quoted at 106 points.

Sergio [31]

Answer:

$318

Step-by-step explanation:

The treasury bond is $10,000

The current yield is 3%

= 3/100

=0.03

It is quoted at 106 points

The first step is to calculate the price of the bond

Price of the bond= $10,000×106/100

= $10,000×1.06

= $10,600

Therefore the annual interest can be calculated as follows

Annual interest= $10,600×0.03

= $318

Hence the annual interest is $318

7 0

3 years ago

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

So

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

So

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

Will give brainliest! Please explain how I solve the ratio 16/32=12/24

goldenfox [79]

To solve, simply simplify each fraction

(16/32)/(16/16) = 1/2

(12/24)/(12/12) = 1/2

True, the equation given to us is true.

hope this helps

8 0

3 years ago

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