Answer: The total money invested in the field will be $1,623.80
Step-by-step explanation:
step 1
Find the dimensions of the field
Let
x -----> the length of the field
y -----> the width of the field
p=2(x+y)
p(4.80)=1,584
p=330m
we know that
The perimeter of the field is equal to
so
330=2(x+y)----> equation A
x=4y-10 ------> equation B
substitute equation B in equation A and solve for y
330=2(4y-10+y)
165=(5y-10)
5y=165+10
y+35
Find the value of x
x=4(35)-10+130
therefore
The length of the field is 130 meters and the width of the field is 35 meters
step 2
Find the area of the field
The area of the field is
A=xy
substitute
A=(130)(35)=4,550m2
step 3
Find the number of bags of seed
Divide the area by 460
4,550/460=9.89 bags
Round up to the nearest whole number
9.89 bags=10 bags
step 4
Find the cost of the seed
(10 )(3.98)=$19.8
step 5
Find the total money invested in the field
1,584+$39.8=$1,623.80
Answer:
0.01, 0.1, 1/8, 1/5
Step-by-step explanation:
can i get the crown plz
Answer:
Slope: -5
Y-intercept: (0,8)
Step-by-step explanation:
Plz mark brainliest.
Answer:
It is not a rectangle
Step-by-step explanation:
A rectangle is a shape with 4 sides, such that we have two pairs of parallel sides, where the length of the parallel sides is equal.
so we have two parallel sides with length L and two parallel sides with length L'.
In this figure ,we can see two sides with length 20 and other two with length 21, and this is a rectangle only if the sides meet at 90°degree angles (this would mean that the opposite sides are parallel)
To see this, we can think that the triangle formed by the diagonal and two sides is a triangle rectangle, then using the Pythagorean theorem we should have that:
20^2 + 21^2 = 28^2
841 = 784
So this is not a triangle rectangle, meaning that the angle between the side of 20 and the side of 21 is not a right triangle, then the figure is not a rectangle.
Therefore, it is not a rectangle
Hope u understand
Please mark the brainliest
Thank You
Step-by-step explanation:
D) 1.02 × 10⁹ kL
Hope it helps you
