A local high school held a two-day fundraiser selling lunches. The equations shown represent the amount of money the school coll
1 answer:
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we have
----> inequality 1
The solution of the inequality 1 is the shaded area below the solid red line
The solution is the region D and region C
-----> inequality 2
The solution of the inequality 2 is the shaded area above the solid blue line
The solution is the region B and region C
The solution of the system is the common area
so
The solution is the region C
see the attached figure
therefore
the answer is the option C
Region C
<h2>>> Answer </h2>
__________
a² = c² - b²
a² = 9² - (√65)²
a² = 81 - 65
a² = 16
a = √16
a = 4