<span>We call the part or the remaining number in a percent problem the amount.</span>
Answer:
585°
Step-by-step explanation:
2
π = 360° = 180/pi
(13pi/4) x (180/pi)
(13/4) x (180/1)
(13/1) x (45/1)
585°
Answer:
The mode for the colors that Santino wore recently is Blue.
Step-by-step explanation:
The mode of a data set is the term or observation that presents most of the time.
The frequency table of different colored polo shirts worn by Santino is:
Color Frequency
Yellow 2
Blue 3
Green 1
Pink 1
Brown 1
Orange 1
Chartreuse 1
Black 1
Puce 1
The color Blue has the highest frequency, i.e. 3.
So, the mode for the colors that Santino wore recently is Blue.
Answer:
The answer is 90 winners.
Step-by-step explanation:
Well, we are given three days. The first day has a rate of 13% winning. The second day has a rate of 13% as well. And the third day has a rate of 11%. You can find this simply by dividing the amount of winners by amount of participants. Now, we must find the mean, or average, of these statistics. We will get 12% as the average rate of winners. How did we get this? By simply adding all three (13+13+11) then dividing by three (37/3), which gives us 12% if we round to a whole number. Now, we can take this number and get 12% of 750. How do we do this? Well, 12% is equal to 0.12. So we will multiply 0.12 by 750. This will give us 90. And there you have your answer.
<em>Alternatively</em>, you could add up the total amount of contestants from the three days. You should end up with 1000. Then add up the total amount of winners from the three days. You should get 120. Divide both of these by 4. The winners will now be 40, and the total contestants will be 250. Now multiply both by 3. The amount of contestants will be 750, and the amount of winners will be 90. This way is a bit easier, but does not always work. <u>Do what is best for you!</u>
Hope this helped!
The intersection is where the sets overlap. picture a Venn diagram (two overlapping circles). The intersection is only the overlap part. So for this problem that would be C. {20}
