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3 years ago

Find the mean of the following data: 10, 16, 15, 14, 8, 21, 10, 5, 19, 18, 4, 5, 16, 12, 10, 9

Mathematics

2 answers:

alisha [4.7K]3 years ago

7 0

Answer:

Step-by-step explanation:

Mean is given by:

Mean= $\frac{Sum of data}{Number of terms }$

Here Sum of data= 10+16+15+14+8+21+10+5+19+18+4+5+16+12+10+9

Sum of data= 192

And,

Number of terms= 16

So,

Mean= $\frac{192}{16}$

Mean= 12

OlgaM077 [116]3 years ago

4 0

The answer: 12

The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count.

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3 years ago

What is the least common multiple of 8 and 9?<br><br><br><br> Enter your answer in the box.

Contact [7]

Answer:

Step-by-step explanation:

The LCM is when you find the lowest factor that 2 or more numbers share.

For 8 and 9,you would just need to keep multiplying each other until you find the same numbers. It would look something like this.

8,16,24,32,40,48,56,64,72..... etc.

9,18,27,36,45,54,63,72,81..... etc.

You can see how they both have the same factor (72), and since that is the lowest factor (which means I can find a lower factor then 72) then your LCM of 8 and 9 should be 72 :)

4 0

3 years ago

Solve using the quadratic formula: 2x2-9x+12=0

marta [7]

Answer:

no solution

Step-by-step explanation:

For getting the nature of solution of the quadratic equation of the form:

ax² + bx + c = 0

We need to find Discriminant which is:

Discriminant (D) = b² - 4ac

If D < 0, there is no solution of equation.
If D = 0, there are two equal and real solution of equation
If D < 0, there are two real and distinct solution of equation

Here we have equation is:

2x² - 9x + 12 = 0

∴ a=2, b = -9, c = 12

⇒ D = 81 - 4 × 2 × 12 = -16 < 0

Hence, there is no solution of given equation.

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3 years ago

How does the area of a circle change if the radius is multiplied by a factor of n, where n is a whole number?

Fantom [35]

Increases but is that what you are asking?

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3 years ago