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3 years ago

Simplify 5^2 · 5^9 1. 5^11 2. 5^18 3. 25^11 4. 25^18

Mathematics

1 answer:

aksik [14]3 years ago

3 0

Answer:

Answer choice 1

Step-by-step explanation:

$5^2\cdot 5^9= \\\\5^{2+9}= \\\\5^{11}$

Therefore, the correct answer choice is choice 1. Hope this helps!

You might be interested in

Consider the recursive formula an = (2 + an-1) / 2

wel

Answer: The correct option is B. The third term is 4.

Explanation:

The given recursive formula is,

$a_n=\frac{2+a_{n-1}}{2}$

It is given that the first term is 10. So,

$a_1=10$

To find third term, first we have to find the second term.

$a_2=\frac{2+a_{2-1}}{2}$

$a_2=\frac{2+a_{1}}{2}$

$a_2=\frac{2+10}{2}$

$a_2=\frac{12}{2}$

$a_2=6$

Therefore the second term is 6.

$a_3=\frac{2+a_{3-1}}{2}$

$a_3=\frac{2+a_{2}}{2}$

$a_3=\frac{2+6}{2}$

$a_3=\frac{8}{2}$

$a_3=4$

Therefore, the correct option is B. The third term is 4.

7 0

4 years ago

Reparametrize the curve with respect to arc length measured from the point where t = 0 in the direction of increasing t. (Enter

jolli1 [7]

Answer:

the answer is incomplete, below is the complete question

"Reparametrize the curve with respect to arc length measured from the point where t = 0 in the direction of increasing t. (Enter your answer in terms of s.) r(t) = 3ti + (1 - 4t)j + (1 + 2t)k r(t(s)) ="

answer

$r(t(s)) = \frac{3s}{\sqrt{29} } i + (1 -\frac{4s}{\sqrt{29} }t)j + (1 + \frac{2s}{\sqrt{29} })k$

Step-by-step explanation:

The step by step procedure is to first determine the differentiate the given vector function

r(t) = 3ti + (1 - 4t)j + (1 + 2t)k

$\frac{d(r(t) = 3ti + (1 - 4t)j + (1 + 2t)k)}{dt} \\r'(t)=3i-4j+2k\\$

since s(t) is the arc length for r(t), which is define as

$s(t)=\int\limits^t_0 {||r'(t)||} \, dt$

if we substitute the value of r'(t) we arrive at

$s(t)=\int\limits^t_0 {||r'(t)||} \, dt\\s(t)=\int\limits^t_0 {\sqrt{3^{2} +4^{2}+2^{2}} \, dt\\s(t)=\int\limits^t_ 0{\sqrt{29} } \, dx\\$

$s(t)=\int\limits^t_ 0{\sqrt{29} } \, dx\\\\s(t)=\sqrt{29} t\\hence \\t(s)=\frac{s}{\sqrt{29} }$

substituting the value of t in to the given vector equation we have

$r(t(s)) = \frac{3s}{\sqrt{29} } i + (1 -\frac{4s}{\sqrt{29} }t)j + (1 + \frac{2s}{\sqrt{29} })k$

4 0

3 years ago

I don’t know how to answer this

oee [108]

Answer:

m∠1=66

m∠3=66

m∠4=114

Step-by-step explanation:

m∠1+m∠2=180

m∠1+114=180

m∠1=66

m∠1=m∠3

66=m∠3

m∠4=m∠2

m∠4=114

5 0

3 years ago

Help asap

sergey [27]

Answer:

There were 250 hamburgers sold on Saturday.

Step-by-step explanation:

∵ A local hamburger shop sold a combined total of 555 hamburgers

and cheeseburgers on Saturday

→ Assume that the shop sold x hamburgers

∵ The shop sold x hamburgers

∵ There were 55 more cheeseburgers sold than hamburgers

→ That means the number of cheeseburgers is greater than the

number of hamburger by 55

∴ The shop sold x + 55 cheeseburgers

∵ The shop sold 555 burgers

→ Add the two types of burgers and equate the sum by 555

∴ x + x + 55 = 555

∴ 2x + 55 = 555

→ Subtract 55 from both sides

∴ 2x + 55 - 55 = 555 - 55

∴ 2x = 500

→ Divide both sides by 2 to find x

∵ $\frac{2x}{2}$ = $\frac{500}{2}$

∴ x = 250

∵ x represents the number of hamburgers

∴ There were 250 hamburgers sold on Saturday.

6 0

3 years ago

(2x+5y)-10(z-3) Can someone tell me how to simplify this plz!?

inna [77]

Answer:

(2x+5y)-10(z-3) We'll multiply the right side term

(2x+5y) -10 * (z-3) then we'll add the terms:

2x + 5y -10z + 30

Step-by-step explanation:

6 0

4 years ago