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Hatshy [7]
3 years ago
8

The table shows a linear relationship between x and y

Mathematics
1 answer:
irga5000 [103]3 years ago
3 0

We have been given a table that shows a linear relationship between x and y. We are asked to find the rate of change change of y with respect to x.

To solve our given problem, we will find the slope of the line passing through the given points.

m=\frac{y_2-y_1}{x_2-x_1}

Let us find slope of line using points (-20,96) and (-2,15).

m=\frac{15-96}{-2-(-20)}

m=\frac{-81}{-2+20}

m=\frac{-81}{18}

m=-4.5

Therefore, the rate of change of y with respect to x is -4.5.

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Write the equation of the conic section below.
tangare [24]

Answer:

(x-3)^2=8(y+1)

Step-by-step explanation:

Standard form of a parabola with a vertical axis of symmetry:

(x-h)^2=4p(y-k) \quad \textsf{where}\:p\neq 0

\textsf{Vertex}=(h, k)

\textsf{Focus}=(h,k+p)

\textsf{Directrix}:y=(k-p)

\textsf{Axis of symmetry}:h=k

If p > 0, the parabola opens upwards, and if p < 0, the parabola opens downwards.

From inspection of the graph:

  • Vertex = (3, -1)
  • Directrix = y = -3

Therefore:

  • h = 3
  • k = -1
  • k - p = -3

Use the Directrix equation to find p

⇒ y = (k - p)

⇒ -3 = -1 - p

⇒ p = 2

Therefore the equation of the conic section is:

\implies (x-3)^2=4\cdot 2(y-(-1))

\implies (x-3)^2=8(y+1)

Rearranging in standard form ax^2+bx+c:

\implies (x-3)^2=8y+8

\implies x^2-6x+9-8=8y

\implies x^2-6x+1=8y

\implies y=\dfrac{1}{8}x^2-\dfrac{3}{4}x+\dfrac{1}{8}

7 0
3 years ago
If the midpoints of the sides of triangle EFG shown below were connected
Ronch [10]

Answer:

Choice 1) 181.5 mm

Step-by-step explanation:

41.5+55+85 = 181.5

8 0
3 years ago
I need help with please.
klasskru [66]
The answer is C for me! hope this helps good luck.
3 0
3 years ago
What are the steps to get the answer
Arlecino [84]

-1/4 x 2/7

 multiply the 2 top numbers and then multiply the 2 bottom numbers

1*2 = 2+4*7 =28

 so answer is -2/28 which can reduce to - 1/14

7 0
3 years ago
Find the determinancof the matrix Q.
stepan [7]

Using a Laplace expansion along the first column, we have

\det Q=2\det\begin{bmatrix}2&1\\-1&6\end{bmatrix}+3\det\begin{bmatrix}3&4\\-1&6\end{bmatrix}+5\det\begin{bmatrix}3&4\\2&1\end{bmatrix}

The determinant of a 2x2 matrix is trivial,

\det\begin{bmatrix}a&b\\c&d\end{bmatrix}=ad-bc

So we have

\det Q=2\cdot13+3\cdot22+5\cdot(-5)=67

5 0
4 years ago
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