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mixas84 [53]
3 years ago
12

Solve linear equation for x 2x-1=3

Mathematics
2 answers:
gulaghasi [49]3 years ago
7 0

Answer:

x=2

Step-by-step explanation:

2x-1=3

+1      +1

2x=4

/2  /2

x=2

Ilya [14]3 years ago
3 0
X=2

Add 1 to both sides
2x=4

Divide by 2
X=2
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In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b
madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding (ax+by)^7 using Binomial expansion, we have that:

(ax+by)^7 =

(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7

= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7

We have that the coefficients of the first two terms are 128 and -224.

For the first term:

=> a^7 = 128

=> a = \sqrt[7]{128}\\ \\\\a = 2

For the second term:

a^6b = -224

b = \frac{-224}{a^6}

b = \frac{-224}{2^6} \\\\\\b = \frac{-224}{64} \\\\\\b = 3.5

Therefore, a = 2, b = 3.5

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stiks02 [169]

Answer:

A. -2x+y=10

Step-by-step explanation:

Given:

The equation of a line is given as:

y-4=2(x+3)

The standard form of an equation of a line is of the form:

Ax+By=C, where, A, B and C are constants.

Now, we have to rearrange the above equation in standard form.

y-4=2(x+3)

Distribute 2 to x+3. This gives,

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Add 4 on both sides. This gives,

y-4+4=2x+6+4\\y=2x+10

Now, add -2x on both sides. This gives,

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