Patrick has just finished building a pen for his new dog. The pen is 3 feet wider than it is long. He also built a doghouse to p
ut in the pen which has a perimeter that is equal to the area of its base. After putting the doghouse in the pen, he calculates that the dog will have 178 square feet of space to run around inside the pen. He also finds that the perimeter of the pen is 3 times greater than the perimeter of the doghouse.
If x represents the length of the pen and y represents the area of the doghouse, then which of the following systems of equations can be used to determine the length and width of the pen and the area of the doghouse?
If x represents the length of the pen and y represents the area of the doghouse, then which of the following systems of equations can be used to determine the length and width of the pen and the area of the doghouse?
1 answer:
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Answer:
Option (B) is true i.e segment B'D' will run through (2,2) and will be longer than the segment BD.
Step-by-step explanation:
As the assumption quadrilateral ABCD is shown in figure a.
First located the center of the dilation which is located at (2,2) as shown in figure b.
The next thing we want to do is to determine the distance of the center of dilation to each of the points of quadrilateral ABCD as shown in figure b.
Let’s just start with the distance from the center to the point A, but notice we don’t have to move up and down in y direction. So, what we have to do is to increase this by the factor 2. Because this horizontal distance is 1 i.e. the distance from dilation center (2,2) to point A, we just have to multiply by 2 which would be a distance of 2 and this point right here will be the new location of point A’ (0,2).
And the distance from the center to the point C is the horizontal distance of 2 i.e. the distance from dilation center (2,2) to point C, we just have to multiply by 2 which would be a distance of 4 and this point right here will be the new location of point C’ (6,2).
And the distance from the center to the point B is the upward vertical distance of 1 i.e. the distance from dilation center (2,2) to point B, we just have to multiply by 2 which would be a vertical distance of 2 and this point right here will be the location of point B’ (2,4).
And similarly the distance from the center to the point D is the downward vertical distance of 1 i.e. the distance from dilation center (2,2) to point D, we just have to multiply by 2 which would be a vertical distance of 2 and this point right here will be the location of point D’ (2,0).
So, Quadrilateral A'B'C'D' is dilated by a scale factor of 2 centered around (2, 2).
Just notice in figure b that the segment B'D' will run through (2,2) and will be longer than the segment BD.
<u>So,option (B) is true</u> <u>i.e segment</u><u> </u><u>B'D' will run through (2,2) and will be longer than the segment BD.</u>
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