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zmey [24]
4 years ago
15

What is 3x^3 - 11x^2 - 26x + 30 divided by x-5?

Mathematics
2 answers:
Arte-miy333 [17]4 years ago
4 0

Answer:

3x^2+4x-6 is correct

DiKsa [7]4 years ago
3 0

Answer:

Most likely the answer is

3x^2+4x-6

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What is the fewest pairs of corresponding parts that have to be congruent to establish that two triangles are congruent? Once yo
sveticcg [70]

It seems there are always three pairs: SSS, side side side; SAS, side angle side; ASA, angle side angle.

For a right triangle (HL, LL) it seems there are only two items needed, but that's because we already know one angle (it's right).

Once we have congruent triangles, all the corresponding parts are congruent.  That's three sides and and three vertices, so I'd answer six.  Of course almost everything about the triangles is the same, the area, the perimeter, etc.



3 0
3 years ago
What are three equivalent ratio for 12/14
defon
12/14  can be simplified, and that would be an equivalent ratio.  Divide 12 and 14 both by 2, and then you get 6/7.

Another equivalent ratio is 120/140.  To get this ratio, I merely multiplied both the numerator and denominator of the ratio by 10.

You can get an infinite amount of equivalent ratios for 12/14.  All you have to do is make sure that whatever you multiply one part of the ratio by, you have to multiply the other part of the ratio by the same thing.

A final example is 60/70.  I just multiplied both 12 and 14 by 5.



8 0
3 years ago
Read 2 more answers
A farmer produces both beans and corn on her farm. If she must give up 16 bushels of corn to be able to get 6 bushels of beans,
lawyer [7]

Answer:

2.67 bushels of corn

Step-by-step explanation:

We can see it in the picture.

3 0
4 years ago
PLEASE ANSWER QUICK (40 POINTS)
natta225 [31]

Answer:

a

Step-by-step explanation:

it's the opposite side of the transaction line.

8 0
3 years ago
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Which of the following represents the set of possible rational roots for the
vichka [17]
Answer: plus or minus 1, 1/2, 2, 5, 5/2, and 10


Explanation:

To find the possible roots

We first find the factor of the constant term:

10: 1, 2, 5, 10

Then we find the factor of leading coefficient:

2: 1, 2

And the possible rational roots are:

Plus or minus [1/1, 1/2, 2/1, 2/2, 5/1, 5/2, 10/1, 10/2]

Then we get rid of the duplicate:

Plus or minus [1, 1/2, 2, 5, 5/2, 10]

3 0
3 years ago
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