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maksim [4K]
3 years ago
15

Which expression is equivalent to the given expression?

Mathematics
2 answers:
Anni [7]3 years ago
6 0

Answer:

The answer is the option D x(19-23)

Step-by-step explanation:

we have

19x-23x

Factor the term x in the expression

x(19-23)

Alborosie3 years ago
5 0
The answer is D because of the distributive property.

You would distribute x to 19 and -23 to make it equivalent to the given equation
 
I hope that helps!
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What is the square root of 4
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Answer:

2

Step-by-step explanation:

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2 years ago
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A basketball game a team made 52 successful shots they were a combination of 1- and 2- point shots the team scored 86 points in
jasenka [17]

Answer: 15

Step-by-step explanation:

x = one point shots

y = two point shots

 

1) Setup your equations.

 

x + y = 52

x + 2y = 89

 

2) Isolate a variable.

 

x = 52-y

 

3) Plug in.

 

(52-y) + 2y = 89

52 +y =89

y=37

 

4) Solve for x.

 

x = 52 -37

x=15

 

5) Check your answer.

 

15 + 2(37) = 89

15+74=89

89=89

 

37+15 = 52

52=52

x = one point shots

y = two point shots

 

1) Setup your equations.

 

x + y = 52

x + 2y = 89

 

2) Isolate a variable.

 

x = 52-y

 

3) Plug in.

 

(52-y) + 2y = 89

52 +y =89

y=37

 

4) Solve for x.

 

x = 52 -37

x=15

 

5) Check your answer.

 

15 + 2(37) = 89

15+74=89

89=89

 

37+15 = 52

52=52

8 0
2 years ago
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6(1) = 16<br> 6(n) = b(n − 1) + 1<br> Find the 2-term in the sequence.
Tresset [83]

Answer:

17

Step-by-step explanation:

Given

b(1)=16\\ \\b(n)=b(n-1)+1

Finding the second term of the sequence means to find b(2). To find b(2) substitute n=2 into the second expression:

b(2)=b(2-1)+1\\ \\b(2)=b(1)+1\\ \\b(2)=16+1\\ \\b(2)=17

6 0
3 years ago
Round 27,372 to the nearest ten thousand.
grin007 [14]

Answer:

30,000

Step-by-step explanation:

7 is rounded up, so 2 + 1 is 3, therefore the answer is 30,000

6 0
3 years ago
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By what expression can we multiply 2xt^3 to get 32x^3 t^8 PLEASE HELP
Salsk061 [2.6K]

Answer:

16x^2 t^5

Step-by-step explanation:

2 * 16 = 32

x * x^2 = x^3

t^3 * t^5 = t^8

2x t^3 * 16x^2 t^5 = 32x^3 t^8

3 0
3 years ago
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