X+4/4=x/x-2 A:{-4,2} B:{-2,4} C:{}
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Given:
Slips of paper numbered 1 to 15 are placed in a box.
To find:
The probability that the number picked is either a multiple of 5 or an odd number.
Solution:
We have,
Total outcomes = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15
No. of total outcomes = 15
Multiple of 5 are 5, 10, 15.
Odd numbers are 1, 3, 5, 7, 9, 11, 13, 15.
Number that are either a multiple of 5 or an odd number are 1, 3, 5, 7, 9, 10, 11, 13, 15.
No. of favorable outcomes = 9
We know that,
Therefore, the probability that the number picked is either a multiple of 5 or an odd number is 0.6.