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MissTica
3 years ago
15

X+4/4=x/x-2 A:{-4,2} B:{-2,4} C:{}

Mathematics
1 answer:
Andreyy893 years ago
3 0

Answer:

<u>The correct answer is B. {-2,4}</u>

Step-by-step explanation:

Let's solve for x, this way:

x + 4/4 = x /x -2

(x + 4) * ((x - 2) = 4 * x

x² - 2x + 4x -8 = 4x

x² - 2x + 4x -8 - 4x = 0

x² - 2x  -8 = 0

(x - 4) * (x +2) = 0

x - 4 = 0

x + 2 = 0

x₁ = 4

x₂ = - 2

<u>The correct answer is B. {-2,4}</u>

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Lisa [10]

Answer:

f(x) = 4x^2 - 3x + 6

Step-by-step explanation:

Quadratic function is given as f(x) = ax^2 + bx + c

Let's find a, b and c:

Substituting (0, 6):

6 = a(0)^2 + b(0) + c

6 = 0 + 0 + c

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Now that we know the value of c, let's derive 2 system of equations we would use to solve for a and b simultaneously as follows.

Substituting (2, 16), and c = 6

f(x) = ax^2 + bx + c

16 = a(2)^2 + b(2) + 6

16 = 4a + 2b + 6

16 - 6 = 4a + 2b + 6 - 6

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10 = 2(2a + b)

\frac{10}{2} = \frac{2(2a + b)}{2}

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Substituting (3, 33), and c = 6

f(x) = ax^2 + bx + x

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33 = 9a + 3b + 6

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27 = 9a + 3b

27 = 3(3a + b)

\frac{27}{3} = \frac{3(3a + b)}{3}

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Subtract equation 1 from equation 2 to solve simultaneously for a and b.

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The quadratic function that represents the given 3 points would be as follows:

f(x) = ax^2 + bx + c

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