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Anni [7]
3 years ago
7

(X^4/6y)^-2 (y-2/4x-1)^3

Mathematics
1 answer:
Arada [10]3 years ago
8 0

Answer:

{x,y} = {1/3,1/9}

Step-by-step explanation:

Solution :

{x,y} = {1/3,1/9}  

 

System of Linear Equations entered :

  [1]    4x + 6y = 2

  [2]    -4x + 3y = -1

Graphic Representation of the Equations :

   6y + 4x = 2        3y - 4x = -1  

 

 

Solve by Substitution :

// Solve equation [2] for the variable  y  

 

 [2]    3y = 4x - 1

 [2]    y = 4x/3 - 1/3

// Plug this in for variable  y  in equation [1]

  [1]    4x + 6•(4x/3-1/3) = 2

  [1]    12x = 4

// Solve equation [1] for the variable  x  

  [1]    12x = 4  

  [1]    x = 1/3  

// By now we know this much :

   x = 1/3

   y = 4x/3-1/3

// Use the  x  value to solve for  y  

   y = (4/3)(1/3)-1/3 = 1/9  

Solution :

{x,y} = {1/3,1/9}

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3 years ago
Rewrite the expression (19x3 – 5x2 + 6x – 2)/(x + 1) in the form q(x) + r(x)/b(x) where q(x) = quotient, r(x) = remainder, and b
wolverine [178]

We are asked to perform the long division on the following expression.

\frac{(19x^3-5x^2+6x-2)}{(x+1)}

Let us perform the long division.

So, we have

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Remainder: r(x) = -32

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Therefore, the equivalent expression is

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The 3rd option is the correct answer.

7 0
1 year ago
Find the minimum and maximum values of the function subject to the given constraint. (if an answer does not exist, enter dne.) f
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Via Lagrange multipliers:

L(x,y,\lambd)=x^2y+x+y+\lambda(xy-5)
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L_y=x^2+1+\lambda x=0
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\underbrace{10}_{2xy}+1+\lambda y=0\implies \lambda=-\dfrac{11}y
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- - -

Another way to do this is to make f(x,y) a function independent of y, which is made possible by the constraint.

xy=5\implies y=\dfrac5x
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and so on.
8 0
3 years ago
A zucchini plant in Darnell's garden was 12 centimeters tall when it was first planted. Since then, it has grown approximately 0
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Answer:

(a) Find out the  a rule to describe the function.

To prove

Let us assume that the days be represted by d .

Let us assume that the height of plant be represted by y.

As given

A zucchini plant in Darnell’s garden was 12 centimeters tall when it was first planted.

it has grown approximately 0.5 centimeter per day.

Than the function becomes

y = 12 + 0.5 × d

y = 12 + 0.5d

(b) Find out after how many days will the zucchini plant be 0.195 meter tall .

To prove

Let us assume that the days be represted by d .

As given

A zucchini plant in Darnell’s garden was 12 centimeters tall when it was first planted.

it has grown approximately 0.5 centimeter per day.

As

1meter = 100cm

0.195 meter convert into centimeter.

= 19.5cm

Than the equation becomes

12 + 0.5d = 19.5

0.5d = -12 + 19.5

0.5d = 7.5

d = 7.5/10

d = 15 days

Therefore 15 days will the zucchini plant be 0.195 meter tall .

7 0
3 years ago
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