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bulgar [2K]
3 years ago
13

Which table of values corresponds to the graph below? On a coordinate plane, a line goes through points (0, 0), (3, 1), and (6,

2). A 2-column table with 4 rows. Column 1 is labeled x with entries negative 3, 0, 3, 6. Column 2 is labeled y with entries negative 1, 0, 1, 2. A 2-column table with 4 rows. Column 1 is labeled x with entries negative 1, 0, 1, 2. Column 2 is labeled y with entries negative 3, 0, 3, 6. A 2-column table with 4 rows. Column 1 is labeled x with entries negative 1, 0, 1, 6. Column 2 is labeled y with entries negative 1, 0, 1, 2. A 2-column table with 4 rows. Column 1 is labeled x with entries negative 1, 0, 1, 2. Column 2 is labeled y with entries negative 1, 0, 1, 6.
Mathematics
2 answers:
FrozenT [24]3 years ago
6 0

Answer:

Table 1

Step-by-step explanation:

Points on the graph:

  • (0, 0), (3,1), (6,2)

Points according to tables, compared to points on the graph:

A 2-column table with 4 rows. Column 1 is labeled x with entries negative 3, 0, 3, 6. Column 2 is labeled y with entries negative 1, 0, 1, 2.

  • (-3, -1), (0,0), (3,1), (6,2)- yes

A 2-column table with 4 rows. Column 1 is labeled x with entries negative 1, 0, 1, 2. Column 2 is labeled y with entries negative 3, 0, 3, 6.

  • (-1,-3), (0, 0), (1,3), (2, 6)- not matching

A 2-column table with 4 rows. Column 1 is labeled x with entries negative 1, 0, 1, 6. Column 2 is labeled y with entries negative 1, 0, 1, 2.

  • (-1,-1), (0,0), (1,1), (6,2) - not matching

A 2-column table with 4 rows. Column 1 is labeled x with entries negative 1, 0, 1, 2. Column 2 is labeled y with entries negative 1, 0, 1, 6.

  • (-1, -1), (0, 0), (1,1), (2,6)- not matching
r-ruslan [8.4K]3 years ago
5 0

Answer:

table 1 I took the edge test

Step-by-step eplanation:

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The critical value of <em>z</em> for 99% confidence interval is 2.5760.

The 99% confidence interval for population mean number of lightning strike is (7.83 mn, 8.37 mn).

Step-by-step explanation:

Let <em>X</em> = number of lightning strikes on each day.

A random sample of <em>n</em> = 23 days is selected to observe the number of lightning strikes on each day.

The random variable <em>X</em> has a sample mean of, \bar x=8.1\ mn and the population standard deviation, \sigma=0.51\ mn.

The (1 - <em>α</em>)% confidence interval for population mean <em>μ</em> is:

CI=\bar x\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

Compute the critical value of <em>z</em> for 99% confidence interval is:

z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.5760

*Use a <em>z</em>-table.

The critical value of <em>z</em> for 99% confidence interval is 2.5760.

Compute the 99% confidence interval for population mean number of lightning strike as follows:

CI=\bar x\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}\\=8.1\pm2.5760\times\frac{0.51}{\sqrt{23}}\\=8.1\pm0.2738\\=(7.8262, 8.3738)\\\approx(7.83, 8.37)

Thus, the 99% confidence interval for population mean number of lightning strike is (7.83 mn, 8.37 mn).

The 99% confidence interval for population mean number of lightning strike  implies that the true mean number of lightning strikes lies in the interval (7.83 mn, 8.37 mn) with 0.99 probability.

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