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Kaylis [27]
3 years ago
5

Valiant Petro products refines crude oil to produce gasoline and kerosene. Joint costs incurred during the month of May were $1,

800,000. Gasoline requires further processing to be marketable and hence a further processing cost of $100,000 was incurred. Kerosene also requires further processing to be marketable and hence a further processing cost of $200,000 was incurred. Gasoline was sold at $4 per gallon and kerosene at $3.50 per gallon. During the month of May, 500,000 gallons of gasoline and 600,000 gallons of kerosene were processed. What is the production cost per gallon of gasoline for the month of May using the NRV method? Assume there was no beginning inventory.
Business
1 answer:
arsen [322]3 years ago
5 0

Answer: $1,400,000

Explanation:

Joint cost = $1,800,000

Further processing cost(Gasoline) =$100,000

Further processing cost(kerosene) =$200,000

Price of gasoline = $4 per gallon

Price of kerosene = $3.50 per gallon

Processed gasoline in May = 500,000

Processed kerosene in May = 600,000

Allocation of joint cost(Gasoline) = (Total cost × share ratio)

Share ratio = further processing cost of component ÷ total further processing cost

[$1,800,000 × ( 100000 ÷ 300000)]

($1,800,000 × 0.33333333) = 599,999.999

Net realizable value = (Final sales price - processing cost)

[ $(500,000×4) - $600,000]

$2,000,000 - $600,000

$1,400,000

Production cost of gasoline is $1,400,000

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Answer:

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Explanation:

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3 years ago
Which is cheaper: eating out or dining in? the mean cost of a flank steak, broccoli, and rice bought at the grocery store is $13
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Answer:

H_o: \mu \geq 13.04\\H_{\alpha}: \mu \geq 13.04

b) 0.0751

c) We cannot afirm whether eating out or dinning in is cheaper

d) do not reject neither.

<u>Questions:</u>

(a). Develop appropriate hypotheses for a test to determine whether the sample data support the conclusion that the mean cost of a restaurant meal is less than fixing a comparable meal at home.

(b). Using the sample from the 100 restaurants, what is the p -value?

(c). At α = .05 ,what is your conclusion?

(d). Repeat the preceding hypothesis test using the critical value approach

Explanation:

(b)

\frac{X-\mu}{\sigma \sqrt{n} } = P_v\\\frac{12.75-13.04}{2 \sqrt{100} } = -1.45

We use excel function to get the Pz which is .0751

(c). 0.0751 > .05 , We cannot reject the hypotesis. Thus, we can neither say dinning in is more cheap nor eating out is cheaper.

(d). With = 99 , t .05 = −1.66 Reject H 0 if ? ≤ −1.66 −1.45 > −1.66 , do not reject

Degrees of freedom = n − 1 = 99 and Pz of 0.05 = -1.66

Reject when Pz < of -1.66

-1.45 > 1.66 threfore we cannot reject the hypotesis.

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<span>the correct answer is

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Answer:

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