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sweet [91]
3 years ago
6

HURRY PLEASE HELP

Mathematics
1 answer:
Mrac [35]3 years ago
8 0

Answer:

The answer is D

Step-by-step explanation:

I tested this in apex learning and got 100 so its true.

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What is an equation of a circle with center (2,7) and radius 4?
goblinko [34]

Equation of a circle:

(x - h)^2 + (y - k)^2 = r^2


In this case:

<span>center (2,7) and radius 4 so h = 2, k = 7 and r = 4

</span>Equation:

(x - 2)^2 + (y - 7)^2 = 4^2

(x - 2)^2 + (y - 7)^2 = 16


Hope it helps.

8 0
4 years ago
A restaurant manager wants to purchase 200 sets of dishes. one design costs ​$15 per​ set, while another costs ​$55 per set. if
vivado [14]
Hello,

Let's solve this problem mathematically.

For first design...

f = 200 \times 15 = 3000

For second design...

s = 200 \times 55 = 11000

To use an entire budget for design she must order.

For first design

5800÷3000 = 1.93f

or
For second design

5800÷11000=0.52s

Hope this helps answer your question!
r3t40
5 0
3 years ago
There were 15 students running in a race. How many different arrangements of first, second, and third place are possible?
viktelen [127]

Answer:

The area 2730 possible arrangements of first, second, and third place.

Step-by-step explanation:

The order in which the students finish is important. For example A, B and C is a different finishing order(outcome) than B, A and C. So we use the permutations formula to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

In this question:

3 from a set of 15. So

P_{(15,3)} = \frac{15!}{(15-3)!} = 2730

The area 2730 possible arrangements of first, second, and third place.

7 0
4 years ago
How to figure out 2.73+0.003+0.158
Zinaida [17]
Fun! 

Line Up the decimals like a vertical addition problem.

Answer: 2.89100
7 0
3 years ago
Read 2 more answers
Factor out the gcf -15y - 25<br>help me plzzzz​
denpristay [2]

Answer: -5(3y+5)

Step-by-step explanation:

5 0
3 years ago
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