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sp2606 [1]
4 years ago
5

Jean poured water into a rectangular tank at the right until is was 2/3 full. Then she poured some of the water out until it was

2/5 full. How much water did she pour out of the tank? Give your answer in millimeters.
Mathematics
2 answers:
Archy [21]4 years ago
8 0

Answer:

The amount of water she poured out of the tank is 27,000 m³.

Step-by-step explanation:

To answer the question, we take the dimensions of the tank as

Width = 0.5 m

Length = 0.2 m

Height = 1 m

Therefore, if the tank was was filled to 2/3 of the volume, then we have

Volume of water in the tank = 2/3 × 0.5 m × 0.2 m × 1 m

= 0.067 m³

She then poured out water until the tank was 2/5 full. That is

2/5 × 0.5 m × 0.2 m × 1 m = 0.04 m³

Therefore, the amount of water she poured out of the tank is

0.067 m³ - 0.04 m³ = 0.027 m³

However, 1 m³ = 1 × 10⁶ mm³

Therefore 0.027 m³ = 27,000 mm³

The amount of water she poured out of the tank = 27,000 m³.

jonny [76]4 years ago
4 0

Answer:

Jean poured 4/15 of the contents of the water out which is the equivalent of 267 milliliters (assuming the size of the tank is 1 liter)

Step-by-step explanation:

Let's assume the Tank size is 1 liter

Jean filled the tank 2/3 full

2/3 = 0.667

Jean reduced the water level to 2/5 full

2/5 = 0.40

Jean poured 0.667 minus 0.40 water out of the tank = 0.267

0.267 = 4/15

0.267 of 1 liter = 0.267 x 1000 = 267 Milliliters

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A survey is conducted to find out whether people in metropolitan areas obtain their news from television (Event T), an newspaper
MrMuchimi

Answer:

e) P ( R' | T ) = 0.62857

f)  P ( T' | N ) = 0.32258

g)  P ( R' | N ) = 0.70968

h) P ( T' | N&R ) = 5/6

Step-by-step explanation:

Given:

- The probability of Television as news source P ( T ) = 0.7

- The probability of Newspaper as news source P ( N ) = 0.62

- The probability of Radio as news source P ( R ) = 0.46

- The probability of Television & Newspaper as news source P (T&N) = 0.42

- The probability of Television & Radio as news source P (T&R) = 0.26

- The probability of Radio & Newspaper as news source P (R&N) = 0.18

- The probability of all 3 as news source P ( T & R & N ) = 0.03

Find:

Given that TV is a news source, what is the probability that radio is not a news source?

Given that newspaper is a news source, what is the probability that TV is not a news source?

Given that newspaper is a news source, what is the probability that radio is not a news source?

Given that both newspaper and radio are news sources, what is the probability that TV is not a news source?

Solution:

- We will first compute the individual probability of each event occurring alone.

   P (Television is the only news source) = P(T) - P(T&R) - P(T&N) + P(T&N&R)

   P ( Only Television ) = P ( only T ) = 0.7 - 0.42 - 0.26 + 0.03 = 0.05

   P (Newspaper is the only news source) = P(N)-P(N&R)-P(T&N)+P(T&N&R)

   P ( Only Newspaper ) = P ( only N ) = 0.62 - 0.18 - 0.42 + 0.03 = 0.05

   P (Radio is the only news source) = P(R) - P(T&R) - P(N&R) + P(T&N&R)

   P ( Only Radio ) = P ( only R ) = 0.46 - 0.26 - 0.18 + 0.03 = 0.05

- Now for part e)

   We are asked for a conditional probability of the form as follows:

            P ( R' | T ) = P ( R' & T ) / P ( T )

   First compute the probability that next news source is not Radio provided it is already a source of TV.                              

            P ( R' & T ) =  P( only T ) + P ( only T & N ) = 0.05 + 0.42 - 0.03 = 0.44

Hence,

            P ( R' | T ) = 0.44 / 0.7

            P ( R' | T ) = 0.62857

- Now for part f)

   We are asked for a conditional probability of the form as follows:

            P ( T' | N ) = P ( T' & N ) / P ( N )

   First compute the probability that next news source is not TV provided it is already a source of Newspaper.                              

            P ( T' & N ) =  P( only N ) + P ( only R & N ) = 0.05 + 0.18 - 0.03 = 0.2

Hence,

           P ( T' | N ) = 0.2 / 0.62

           P ( T' | N ) = 0.32258

- Now for part g)

   We are asked for a conditional probability of the form as follows:

            P ( R' | N ) = P ( R' & N ) / P ( N )

   First compute the probability that next news source is not Radio provided it is already a source of Newspaper.                              

            P ( R' & N ) =  P( only N ) + P ( only T & N ) = 0.05 + 0.42 - 0.03 = 0.44

Hence,

            P ( R' | N ) = 0.44 / 0.62

            P ( R' | N ) = 0.70968

- Now for part h)

   We are asked for a conditional probability of the form as follows:

            P ( T' | N&R ) = P ( T' & N & R) / P ( N & R )

   First compute the probability that next news source is not TV provided it is already a source of both radio and Newspaper.                              

            P ( T' & N & R) = P ( only N & R ) = 0.18 - 0.03 = 0.15

Hence,

            P ( T' | N&R ) = 0.15 / 0.18

            P ( T' | N&R ) = 5/6

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Step-by-step explanation:  

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