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3 years ago

Find the product. Select the answer that is in simplest form. 2/3 × 4 /5 = ?

Mathematics

2 answers:

liraira [26]3 years ago

8 0

It is so simple. Multiply 2 to 4 and 3 to 5
2/3 x 4/5 = 8/15

Tanzania [10]3 years ago

8 0

2/3 × 4/15 = 8/15 it's really simple just keep practicing

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Find the distance between each pair of points. round your answer to the nearest tenth, if necessary. (-8, -5), (-4, 3)

Anuta_ua [19.1K]

The answer would be 8.9

8 0

3 years ago

A point in rectangular coordinates is given. Convert the point to polar coordinates. Round your answers to two decimal places.

postnew [5]

Answer:

(√74, 54.46°)

Step-by-step explanation:

The rectangular coordinate point is given as; (5, 7)

Now, converting rectangular coordinates to polar coordinates is done by;

(r, θ)

Where, r is the magnitude while θ is the angle

r = √(5² + 7²)

r = √74

tan θ = (7/5)

θ = tan^(-1) 1.4

θ = 54.46°

Thus,polar coordinate is; (√74, 54.46°)

3 0

2 years ago

One box holds 16 crayons. Another box hold 24 crayons. Write a sentence using words that compares the crayons in the two boxes

Triss [41]

24 is greater than 16. Or in mathematical terms 24 > 16

7 0

3 years ago

Read 2 more answers

Find the oth term of the geometric sequence 9, -27, 81, ...

Novosadov [1.4K]

It would b 9 x (-3^(x-1))

6 0

2 years ago

In a bag of m&m's there are 5 brown 6 yellow 4 blue 3 green and 2 orange. What's the probability of getting 3 yellow m&m

olasank [31]

There are 5+6+4+3+2=20 m&m's in the bag.
Calculate in how many ways you can choose 3 m&m's from 20:
$_{20} C _3=\frac{20!}{3!(20-3)!}=\frac{20!}{3! \times 17!}=\frac{17! \times 18 \times 19 \times 20}{6 \times 17!}=\frac{18 \times 19 \times 20}{6}=3 \times 19 \times 20= \\
=1140$

There are 6 yellow m&m's.
Calculate in how many ways you can choose 3 m&m's from 6:
$_6 C _3 = \frac{6!}{3!(6-3)!}=\frac{6!}{3! \times 3!}=\frac{3! \times 4 \times 5 \times 6}{3! \times 6}=\frac{4 \times 5 \times 6}{6}=4 \times 5=20$

The probability is the number of ways of choosing 3 m&m's from 6 m&m's divided by the number of ways of choosing 3 m&m's from 20 m&m's.
$P=
\frac{20}{1140}=\frac{20 \div 20}{1140 \div 20}=\frac{1}{57}$

The probability is 1/57.

4 0

2 years ago