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Aliun [14]
3 years ago
11

11 times what give you 187

Mathematics
2 answers:
mr_godi [17]3 years ago
6 0
17. 187 divided by 11 equals 17.
blagie [28]3 years ago
3 0
11x17=187 hope it helps
-Andrew
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An amount of $15,000 is invested in a fund that has a return of
IrinaVladis [17]

Answer:

$12000 should be invested in a fund with a 4% return.

Step-by-step explanation:

Consider the provided information.

An amount of $15,000 is invested in a fund that has a return of  6%.

We need to calculate how much money is invested in a fund with a 4% return if the  total return on both investments is $1380.

Let $x should be invested in a fund with a 4% return.

The above information can be written as:

1380=15000\times 6\%+x\times 4\%

1380=15000\times \frac{6}{100}+x\times \frac{4}{100}

1380=150\times6+x\times 0.04

1380-900=0.04x\\480=0.04x\\x=12000

Hence, $12000 should be invested in a fund with a 4% return.

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Gary buys a skateboard for<br> $145. What's the total cost<br> including 6% sales tax?
Licemer1 [7]

Answer:

$8.6

Step-by-step explanation:

The total tax is 8 dollars and 60 cents

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Pls solve the simultaneous equation in the attachment.
siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

\frac{x}{2}-\frac{y}{5}=1 ----> equation A

y-\frac{x}{3}=8 ----> equation B

Multiply equation A by 10 both sides to remove the fractions

5x-2y=10 ----> equation C

isolate the variable y in equation B

y=\frac{x}{3}+8 ----> equation D

we have the system of equations

5x-2y=10 ----> equation C

y=\frac{x}{3}+8 ----> equation D

Solve the system by substitution

substitute equation D in equation C

5x-2(\frac{x}{3}+8)=10

solve for x

5x-\frac{2x}{3}-16=10

Multiply by 3 both sides

15x-2x-48=30

15x-2x=48+30

Combine like terms

13x=78

x=6

<em>Find the value of y</em>

y=\frac{x}{3}+8

y=\frac{6}{3}+8

y=10

The solution is the ordered pair (6,10)

Part b) we have

xy=21 ---> equation A

x+5y=22 ----> equation B

isolate the variable x in the equation B

x=22-5y ----> equation C

substitute equation C in equation A

(22-5y)y=21

solve for y

22y-5y^2=21

5y^2-22y+21=0

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

x=22-5(1.4)=15

For y=3

x=22-5(3)=7

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0
4 years ago
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