The net cannot be folded to form a pyramid because the faces that are not a base are not all triangles
If you fold this net up, you will get a triangular prism, NOT A PYRAMID.
A pyramid can have ANY polygon as its base, as long as all the other rest of the shapes are triangles.
Depending on the base, the number of triangles in a net of a pyramid must match the number of sides its particular base has.
For example, if you have a square pyramid turned into a net:
The base is a square (4 sides)
There should be 4 triangles on each side.
Because a pyramid is where all the triangles must meet up at a point.
Hope this helps!
To start, you need to subtract 4x from both sides, that way, x is one one sid of the equation.
I don’t know and i understand that the other one didn’t do it but did you already try searching it?
Answer:
Actually it's not polygon. it's a nonagon. With r=8.65mm″, the law of cosines gives us side a:
a=√{b²+c²−2bc×cos40°}
a=√{149.645−149.645cos40°}
Area Nonagon = (9/4)a²cos40°
=9/4[149.645−149.645cos40°]cot20°
=336.70125[1−cos(40°)]cot(20°)
Applying an identity for the cos(40°) does not get us very far…
= 336.70125[1−(cos2(20°)−1)]cot(20°)
= 336.70125[2−cos2(20°)]cot(20°)
= 336.70125[2−(1−sin2(20°))]cot(20°)
= 336.70125[1+sin2(20°)]cos(20°)sin(20°)
= 336.70125[cot(20°)+sin(20°)cos(20°)]mm²
Answer:
After 460 calls plan 1 is more economical than plan 2
Step-by-step explanation:
Plan 1: 36x + 0y
Plan 2: 13x + 0.05y
36x < 13x + 0.05y
36x - 13x < 0.05y
23x < 0.05y
23/0.05x < y
460x < y
