Answer:
no of 5 kg disks is 3, and no of 2 kg disks is (10-3) i.e. 7
Step-by-step explanation:
Let the no of 2kg disks be a.
Let no of 5 kg disks be b.
2a+5b=29
a+b=10
Using substitution, we have
2(10-b) + 5b=29
20-2b+5b=29
20+3b=29
3b=9
b=3
So no of 5 kg disks is 3, and no of 2 kg disks is (10-3) i.e. 7
He has 11 quarters and 17 dimes.
11 x .25 = 2.75 17 x .1 = 1.7 2.75 + 1.7 = 4.45
Hope this helps
B I have done this before
