Question

If sin Θ = 5 over 6 , what are the values of cos Θ and tan Θ? (2 points)

Answer 1

Cos² (theta) = 1 - (5/6)²
cos² (theta) = 1 - 25/36 = 11/36
cos(theta) = $\sqrt{ \frac{11}{36} }=\pm \frac{ \sqrt{11} }{6}$
tan(theta) = sin(theta) / cos (theta)=$\pm\frac{5/6}{ \sqrt{11}/6 }= \pm \frac{5}{ \sqrt{11} } =\pm \frac{5 \sqrt{11} }{11}$
Answer: D)