OK, let's try with no figure. We have an isosceles triangle sides s,s, and b.
Opposite b is angle t.
Draw the altitude h to bisect t. We have two right triangles, legs b/2 and h, hypotenuse s. The angle opposite b/2 is t/2 so
sin(t/2) = (b/2)/s = b/2s
So we arrived at the first part,
b = 2s sin(t/2)
The area of a triangle with sides s,s and included angle t is
A = (1/2) s² sin t
You didn't write the (-2/7) as a power; you were supposed to do b to the power of -2 over 7, which is what the other person done in your other post regarding this
Answer:
B
Step-by-step explanation:
To find the y- intercept let x = 0
From the table for f(x)
When x = 0 → f(x) = - 4
That is the y- intercept = - 4
Given
g(x) = 3 
let x = 0 , then
g(0) = 3 
[ 
= 1 ]
= 3 × 1
= 3
That is the y- intercept = 3
Thus the y- intercept of g(x) is greater → B
X+y=10 in y-intercept is y=-x+10. 10 is the y intercept. The ordered pair is (0, 10)
