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gulaghasi [49]
4 years ago
10

Simplify the expression: (cosx-1)/sinx + sinx/(cosx +1) ?? I got cosx but the answer is zero?? Je ne sais quoi!!! Btw the questi

on is the top one! Thanks!!!!

Mathematics
1 answer:
Radda [10]4 years ago
8 0
<span> (cosx-1)/sinx + sinx/(cosx +1) =?


\it E = \dfrac{\cos x-1}{\sin x} + \dfrac{\sin x}{\cos x+1} = \dfrac{(\cos x-1)(\cos x+1)+sin^2x}{sin x(\cos x+1)}= &#10;\\\;\\ \\\;\\&#10;= \dfrac{\cos ^2x - 1 +sin^2x}{sin x(\cos x+1)}= \dfrac{\cos ^2x  +sin^2x -1}{sin x(\cos x+1)}= \dfrac{ 1- 1 }{sin x(\cos x+1)}= 0</span>
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The weights of a certain dog breed are approximately normally distributed with a mean of 49 pounds, and a standard deviation of
AlekseyPX

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a. 74.86%

b. 50%

c. 50%

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of 49 pounds, and a standard deviation of 6 pounds.

This means that \mu = 49, \sigma = 6

a. Find the percentage of dogs of this breed that weigh less than 53 pounds.

The proportion is the p-value of Z when X = 53. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{53 - 49}{6}

Z = 0.67

Z = 0.67 has a p-value of 0.7486.

0.7486*100% = 74.86%, which is percentage of dogs of this breed that weigh less than 53 pounds.

b. Find the percentage of dogs of this breed that weigh less than 49 pounds.

p-value of Z when X = 49, so:

Z = \frac{X - \mu}{\sigma}

Z = \frac{49 - 49}{6}

Z = 0

Z = 0 has a p-value of 0.5

0.5 = 50% of dogs of this breed that weigh less than 49 pounds.

c. Find the percentage of dogs of this breed that weigh more than 49 pounds.

1 subtracted by the p-value of Z when X = 49, so:

Z = \frac{X - \mu}{\sigma}

Z = \frac{49 - 49}{6}

Z = 0

Z = 0 has a p-value of 0.5.

1 - 0.5 = 0.5 = 50% of dogs of this breed that weigh more than 49 pounds.

8 0
3 years ago
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