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HACTEHA [7]
3 years ago
14

The Brown's are renting a home and are planning to set up their trash service. They are considering two local companies. Company

A charges a $50 setup fee and $15 per month. This can be represented by the linear function C = 15x + 50. Company B charges $100 for the setup fee and $12 per month. This can be represented by the linear function C = 12x + 100. They are planning to rent their home and use trash service for 6 months. Which statement is true?
A) The cost of using Company B is the same as the cost of using Company A.
B) The cost of using Company B is $32 less than the cost of using Company A.
C) The cost of using Company A is $32 less than the cost of using Company B.
D) The cost of using Company B is $18 less than the cost of using Company A.
Eliminate

Mathematics
2 answers:
Gnesinka [82]3 years ago
8 0
The answer is C. You will plug in 6 for the X value in the equations because they are going to use it for six months. c= A.15(6) + 50  and B.c=12(6) +100.
solving those out A will be $140 and B will be $172.
Viefleur [7K]3 years ago
8 0
Check the picture for the solution.

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3 years ago
Assume the hold time of callers to a cable company is normally distributed with a mean of 5.5 minutes and a standard deviation o
Ierofanga [76]

Answer:

The percent of callers are 37.21 who are on hold.

Step-by-step explanation:

Given:

A normally distributed data.

Mean of the data, \mu = 5.5 mins

Standard deviation, \sigma = 0.4 mins

We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.

Lets find z-score on each raw score.

⇒ z_1=\frac{x_1-\mu}{\sigma}   ...raw score,x_1 = 5.4

⇒ Plugging the values.

⇒ z_1=\frac{5.4-5.5}{0.4}

⇒ z_1=-0.25  

For raw score 5.5 the z score is.

⇒ z_2=\frac{5.8-5.5}{0.4}  

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Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.

We have to work with P(5.4<z<5.8).

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To find the percentage we have to multiply with 100.

⇒ 0.3721\times 100

⇒ 37.21 %

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