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3 years ago

Please help me! Thanks!

Mathematics

1 answer:

tekilochka [14]3 years ago

3 0

Answer:

A) 3(4x -4) -7x

Step-by-step explanation:

if you distribute the 3 and then simplify by combining like-terms, you will get 5x - 12

3(4x - 4) - 7x

12x -12 - 7x

5x -12

~ Luna P.

^_^

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The area of these shapes are?

kipiarov [429]

Answer:
Figure 1:
Area = 390ft^2

Figure 2:
Area = 325.17 ft^2

7 0

3 years ago

Can someone solve these please using the formula AB | a - b | And can you show work

Lana71 [14]

Answer: 1) AC = 13

The formua does not actually apply to all of the problems.

Step-by-step explanation:

1) The absolute value of -8 is added to the absolute value of 5. 8+5=13

2) Subtract the length of the EF from EG to get the length of FG 21 -6 = 15

3) Take what's given and create an equation to solve. 4x + 15 +39 =110. 4x = 110 - (15+39).

4x =110-54. 4x =56. x=56/4. x=14

4) Create another equation. You have two segments that add up to the length of EG, given =23

EF+FG=EG

(2x-12)+(3x-15)=23

5x - 27 = 23

5x= 23+27 5x =50. x = 10

Substitute 10 for x

EF=2(10) -12 EF=8

FG=3(10)-15. FG=15

EF+FG =EG.

8 + 15 = 23

5) 2/5 of 25 is 10 So EF is 10. Subtract from 25 to get FG

FG = 15

I hope this helps you.

4 0

3 years ago

Semicircles

Studentka2010 [4]

Answer:

The area of the shaded portion of the figure is $9.1\ cm^2$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The shaded area is equal to the area of the square less the area not shaded.

There are 4 "not shaded" regions.

step 1

Find the area of square ABCD

The area of square is equal to

$A=b^2$

where

b is the length side of the square

we have

$b=4\ cm$

substitute

$A=4^2=16\ cm^2$

step 2

We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):

The area of circle is equal to

$A=\pi r^{2}$

The diameter of the circle is equal to the length side of the square

$r=\frac{b}{2}=\frac{4}{2}=2\ cm$ ---> radius is half the diameter

substitute

$A=\pi (2)^{2}$

$A=4\pi\ cm^2$

Therefore, the area of 2 "not-shaded" regions is:

$A=(16-4\pi) \ cm^2$

and the area of 4 "not-shaded" regions is:

$A=2(16-4\pi)=(32-8\pi)\ cm^2$

step 3

Find the area of the shaded region

Remember that the area of the shaded region is the area of the square less 4 "not shaded" regions:

$A=16-(32-8\pi)=(8\pi-16)\ cm^2$

---> exact value

assume

$\pi =3.14$

substitute

$A=(8(3.14)-16)=9.1\ cm^2$

8 0

3 years ago

Can someone help me please

Lady bird [3.3K]

Answer: 12.50$

Explanation: 5.25$ (per pound) and he wants 3 pounds so we multiply 5.25x3 which equals 15.75 and then we subtract 3.25 (because of the coupon) which makes your final answer 12.50$

8 0

3 years ago

If Usain Bolt can run a marathon (26.2) in 2 hours and 15 minutes, how fast would he run if he ran at the same constant rate?

inn [45]

Answer:

The speed of Usain Bolt is 0.194 miles per minutes to complete the marathon.

Step-by-step explanation:

Given as :

The Distance of marathon = 26.2 unit

The time taken to complete marathon = 2 hours and 15 minutes

= 120 + 15 = 135 minutes

Let The constant speed of Usain Bolt = S unit per minutes

So, Speed = $\frac{Distance }{Time}$

Or, S = $\frac{26.2 }{135}$

∴ S = 0.194 unit per minutes

Hence The speed of Usain Bolt is 0.194 miles per minutes to complete the marathon. Answer

8 0

3 years ago