Answer:
b. the symbol has or equal to
Step-by-step explanation:
Required
When does an inequality have a solid line
The question is pretty straightforward and the answer is (b) which means that when the symbol has or equal to.
This implies that, the symbol could be:
> or = i.e. 
and it could also be:
< or = i.e. 
Take for instance:
and 
<em>The above expressions will have a solid line</em>
C. It’s goes over two and up three. So therefore L would be (3,2)
Answer:
84? Not sure but pretty sure
Step-by-step explanation:
In a straight line, the word can only be spelled on the diagonals, and there are only two diagonals in each direction that have 2 O's.
If 90° and reflex turns are allowed, then the number substantially increases.
Corner R: can only go to the adjacent diagonal O, and from there to one other O, then to any of the 3 M's, for a total of 3 paths.
2nd R from the left: can go to either of two O's, one of which is the same corner O as above. So it has the same 3 paths. The center O can go to any of 4 Os that are adjacent to an M, for a total of 10 more paths. That's 13 paths from the 2nd R.
Middle R can go the three O's on the adjacent row, so can access the three paths available from each corner O along with the 10 paths available from the center O, for a total of 16 paths.
Then paths accessible from the top row of R's are 3 +10 +16 +10 +3 = 42 paths. There are two such rows of R's so a total of 84 paths.
Hello!!
The domain of any polynomial expression is all real numbers from -infinity to +infinity. This is due to the leading x^2 term!
Hope this helps you understand! Thank you!!
