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2 years ago

75,100,125, what comes next

Mathematics

1 answer:

Alchen [17]2 years ago

8 0

Answer:

150

Step-by-step explanation:

add 25 and you get the next number

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At a restaurant, brunch cost $18.50. As the cost of ingredients rises, the cost of brunch also rises by 40%. What is the new pri

statuscvo [17]

$25.90 because if you move the decimal over one place in 18.50 you get 1.85 that is 10% so you take that times four and get $7.50 add that to 18.50 and you get the answer

6 0

2 years ago

Tina raised the number 3 to a power and then added 19 to the result .She obtained the sum 100. To what power did she raise 3 ?

Romashka-Z-Leto [24]

Answer:

3^4, she raised it to the 4th power

Step-by-step explanation:

3^x+19=100

-19

3^x=81

We can make a table now to find what power of three = 81

Powers of three table

3^1=3 3^2=9 3^3=27 3^4=81

4 0

3 years ago

the sum of ones digit and tens digit is also 10. However, my ones digit is greater than my tens digit. i am a prime number less

Naddik [55]

The number that would fit is 37.

7 0

3 years ago

Use matrices to solve the system of equations if possible. Use Gaussian elimination with back substitution or gauss Jordan elimi

CaHeK987 [17]

In matrix form, the system is given by

$\begin{bmatrix} -1 & 1 & -1 \\ 2 & -1 & 1 \\ 3 & 2 & 1 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} -20 \\ 29 \\ 29 \end{bmatrix}$

I'll use G-J elimination. Consider the augmented matrix

$\left[ \begin{array}{ccc|c} -1 & 1 & -1 & -20 \\ 2 & -1 & 1 & 29 \\ 3 & 2 & 1 & 29 \end{array} \right]$

• Multiply through row 1 by -1.

$\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 2 & -1 & 1 & 29 \\ 3 & 2 & 1 & 29 \end{array} \right]$

• Eliminate the entries in the first column of the second and third rows. Combine -2 (row 1) with row 2, and -3 (row 1) with row 3.

$\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 5 & -2 & -31 \end{array} \right]$

• Eliminate the entry in the second column of the third row. Combine -5 (row 2) with row 3.

$\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 0 & 3 & 24 \end{array} \right]$

• Multiply row 3 by 1/3.

$\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 0 & 1 & 8 \end{array} \right]$

• Eliminate the entry in the third column of the second row. Combine row 2 with row 3.

$\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & 0 & -3 \\ 0 & 0 & 1 & 8 \end{array} \right]$

• Eliminate the entries in the second and third columns of the first row. Combine row 1 with row 2 and -1 (row 3).

$\left[ \begin{array}{ccc|c} 1 & 0 & 0 & 9 \\ 0 & 1 & 0 & -3 \\ 0 & 0 & 1 & 8 \end{array} \right]$

Then the solution to the system is

$\boxed{x=9, y=-3, z=8}$

If you want to use G elimination and substitution, you'd stop at the step with the augmented matrix

$\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 0 & 1 & 8 \end{array} \right]$

The third row tells us that $z=8$ . Then in the second row,

$y-z = -11 \implies y=-11 + 8 = -3$

and in the first row,

$x-y+z=20 \implies x=20 + (-3) - 8 = 9$

5 0

1 year ago

If the radius of a circle is 44 cm, then what is the diameter?

solmaris [256]

Answer:

88cm

Step-by-step explanation:

d=2r=2·44=88cm

3 0

2 years ago

Read 2 more answers