It is given that, B ≅ BC and AD ≅ CD
We need BD perpendicular to AC, then only we can say triangles AXB and CXB are congruent using the HL theorem.
If BD perpendicular to AC, means that AB and CB are the hypotenuse of triangles AXB and CXB respectively.
from the given information ABCD is a square
If BD and AC bisect each other then AX = CX
Then only we can immediately possible to prove that triangles AXD and CXD are congruent by SSS congruence theorem
Square root of 8 = 2.82842712475
Square root of 50 = <span>7.07106781187
</span>
Sum = 9.89949494
If you would like to round, you can go ahead and round 9.89949494 to 9.9
Let me see if I am correct I will get back to u
Answer:
2 x 7
Step-by-step explanation:
a * b = 14
2a + 2b = 18
(a * b)/b = 14/b Dividing both sides by b
a = 14/b
Substitute a in the perimeter equation
2(14/b) + 2b = 18
28/b + 2b = 18
2b - 18 + 28/b = 0
Multiply both sides by b
2b^2 - 18b + 28 = 0
Divide both sides by two
b^2 - 9b + 14 = 0
The Factors of 14 include -2 and -7 which add up to -9
(b - 2) * (b - 7) = 0
This has two answers because b can be either the side that is 2 long or 7 long, so there's no need to go back and solve for a.
2 x 7
Answer:
x = 7 degrees
Step-by-step explanation:
4x-5 = 2x + 9
-2x -2x
2x-5 = 9
+5 +5
2x = 14
2x/2 =14 /2
x= 7