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4 years ago

• is times 3e • 16=24 ?

Mathematics

2 answers:

lara [203]4 years ago

7 0

E=.5

you divide both sides by 16, then divide both sides by 3

ki77a [65]4 years ago

5 0

Answer:

Process:
3e*16=24
Combine like terms by dividing both sides by 16
3e*16/16=24/16
3e=24/16
Simplify the fraction
3e=3/2
Divide both sides by 3 to cancel it out on the left side
3e/3=3/2/3
e= (3/2)/3
Dividing with a fraction is the same as multiplying with the reciprocal of the fraction (we flip it upside down)
e=(3/2)*(1/3)
e=3/6
Simplify the fraction
e=1/2

I hope this helps! Please comment if you have any questions.

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notsponge [240]

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Step-by-step explanation:

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3 years ago

Simplify (3^-2)^4

Ugo [173]

Answer:

Step-by-step explanation:

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4 years ago

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Helpppppp i need to do this before 10:00 or my teacher said I will fail Ayudarr

kotykmax [81]

I thing it is “protagonista” not sure tho

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3 years ago

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mrs_skeptik [129]

Given:

Line a passes through (2, 10) and (4, 13).

Line b passes through (4, 9) and (6, 12).

Line c passes through (2, 10) and (4, 9).

To find:

Which of the lines, if any are perpendicular.

Solution:

If a line passes through two points, then the slope of line is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Line a passes through (2, 10) and (4, 13). So, slope of this line is

$m_a=\dfrac{13-10}{4-2}=\dfrac{3}{2}$

Line b passes through (4, 9) and (6, 12). So, slope of this line is

$m_b=\dfrac{12-9}{6-4}=\dfrac{3}{2}$

Line c passes through (2, 10) and (4,9). So, slope of this line is

$m_c=\dfrac{9-10}{4-2}=\dfrac{-1}{2}$

Product of slopes of to perpendicular lines is -1.

$m_a\cdot m_b=\dfrac{3}{2}\times \dfrac{3}{2}=\dfrac{9}{4}\neq -1$

$m_b\cdot m_c=\dfrac{3}{2}\times \dfrac{-1}{2}=\dfrac{-3}{4}\neq -1$

$m_a\cdot m_c=\dfrac{3}{2}\times \dfrac{-1}{2}=\dfrac{-3}{4}\neq -1$

Therefore, any of these lines are not perpendicular to each other.

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3 years ago

the ordered pairs shown represent a relation: (3, 2) (5, 1) (6, 0) (7, 4) (5, 3). Which number is part of the domain relationshi

Effectus [21]

The domain is all of ur x values and the range is all of the y values.
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3 years ago